Answer:
26
Step-by-step explanation:
from what I got lol , your welcome and have a nice day
Answer:
where is the picture or graph
or something
Step-by-step explanation:
Answer:
It is proved
Step-by-step explanation:
A curve immersed in the three-dimensional sphere is said to be a Bertrand curve if there exists another curve and a one-to-one correspondence between and such that both curves have common principal normal geodesics at corresponding points.
See attachment for the step by step solution of the given problem.
Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
There should only be one step necessary
(4m-1) / m = 4 - 1/m
