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Bumek [7]
4 years ago
12

Help ASAP!!! please show your work as well!

Mathematics
1 answer:
dmitriy555 [2]4 years ago
8 0
Short Answer: pi/6 5pi/6 pi/2 3pi/2
Step One

Pull cos(theta) our of the brackets
cos(theta)*(sin(theta) - 1/2) = 0         Do not divide by cos(theta)

Step Two
Identify the sources of the solution
.
You have 2 sources of solutions for this
The first is cos(theta)

<u>source 1</u>
cos(theta) = 0 
Theta can have 2 values 
pi/2 and (3/2 pi)

<u>Source 2</u>
You also have another source
sin(theta - 1/ 2 = 0
sin(theta) = 1/2
Theta can have 2 values One in quadrant 1 and one in quadrant 2

<em>Quadrant 1</em>
Theta = 30o = 30/180 * pi = pi/6

<em>Quadrant 2</em>
Theta = 180 - 30 = 150o = 150o/180 * pi = (5/6) pi
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