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disa [49]
3 years ago
8

Triple my number add six and subtract my number twice I get my number plus three

Mathematics
1 answer:
liberstina [14]3 years ago
8 0
Let the number be x.

Triple the number means 3x
add 6 means 3x + 6
subtract the number twice 3x + 6 - x - x
the result is the number plus 3 means that the result is x + 3

So, combining these into an equation, we get:
3x + 6 - x - x = x + 3

If we solve this equation for x, we will get:
x + 6 = x + 3
The x will cancel out and we will get : 6 = 3

Therefore, this is a false statement.
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The interarrival time of nuclear particles in a Monte Carlo simulation of a reaction is designed to have a uniform distribution
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Answer:

Incomplete question, but you can use the formulas given to solve it.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

P(X < x) = \frac{x - a}{b - a}

The probability of finding a value between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

The probability of finding a value above x is:

P(X > x) = \frac{b - x}{b - a}

Uniform distribution over an interval from 0 to 0.5 milliseconds

This means that a = 0, b = 0.5

Determine the probability that the interarrival time between two particles will be:

Considering a = 0, b = 0.5, and the question asked, you choose one of the three formulas above.

7 0
3 years ago
727w8w7eueurururuititoy​
SSSSS [86.1K]

Answer:

ok

Step-by-step explanation:

5 0
2 years ago
PLS help I will give brainliest​
Savatey [412]

Answer: 1= X = 8

              2= X = 6

              3= X = 7

              4=  X= 9/13 or X= 0.692307

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2 years ago
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2 years ago
Solve (x + 4)2 – 3(x + 4) – 3 = 0 using substitution. u = Select the solution(s) of the original equation.
bezimeni [28]

Answer:

\dfrac{-5-\sqrt{21}}{2},\ \dfrac{-5+\sqrt{21}}{2}

Step-by-step explanation:

For the equation (x+4)^2-3(x+4)-3=0 use the substitution u=x+4. Then the equation will take look

u^2-3u-3=0.

Solve this quadratic equation:

D=(-3)^2-4\cdot 1\cdot (-3)=9+12=21,\\ \\u_{1,2}=\dfrac{-(-3)\pm \sqrt{21}}{2}=\dfrac{3\pm\sqrt{21}}{2}.

Thus,

x+4=\dfrac{3-\sqrt{21}}{2}\text{ or }x+4=\dfrac{3+\sqrt{21}}{2},\\ \\x_1=\dfrac{3-\sqrt{21}}{2}-4=\dfrac{-5-\sqrt{21}}{2}\text{ or }x_2=\dfrac{3+\sqrt{21}}{2}-4=\dfrac{-5+\sqrt{21}}{2}.

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3 years ago
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