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3 years ago

Simplify the following expressions by using the order of operations

Mathematics

1 answer:

MariettaO [177]3 years ago

5 0

11. 6 + 5 * 2 + (-3)
6 + 10 - 3
16 - 3
13 <==

12. 67 + 84 - 12 * 4 / 16
67 + 84 - 48/16
67 + 84 - 3
148 <==

13. -5 * -6 - 25/5 - 2
30 - 5 - 2
23 <==

14. 18 - (9 + 3) + 2^3
18 - 12 + 8
14 <==

15. -24 / -6 * 2
4 * 2
8 <==

16. 8 [ (26 + 10) - 4(3 + 2)]
8 [ (36 - 4(5)]
8 [ 36 - 20 ]
8 [ 16 ]
128 <==

17. 6 * 3 / 9 * 2 + 1
18/9 * 2 + 1
2 * 2 + 1
4 + 1
5 <==

18. (9 - -4)(-8 - -7)
(9 + 4)(-8 + 7)
13 * -1
-13 <==

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Answer:

Lisa's team have played 24 home games and 25 away games.

Step-by-step explanation:

Given:

Let $x$ represents games played at home.

also $y$ represent games played away.

Total number of games played = 49

∴ $x+y=49 \ \ \ \ equation \ 1$

Now according to given data:

Number of home games won = $\frac{2}{3}$

Number of away game won = $\frac{2}{5}$

Total games won =26

Hence

$\frac{2}{3}x+\frac{2}{5}y=26\\\\\frac{2\times 5}{3\times 5}x+\frac{2\times 3}{5\times 5}y=26\\\\\frac{10}{15}x+\frac{6}{15}y=26\\\\\frac{10x+6y}{15}=26\\\\10x+6y= 26\times 15\\10x+6y = 390\\2(5x+3y)=390\\5x+3y=\frac{390}{5}\\\\5x+3y=195 \ \ \ \ equation \ 2\\$

Now multiplying equation 1 by 3 we get,

$3(x+y)=3\times49\\3x+3y=147 \ \ \ \ \ equation \ 3\\$

Now Subtracting equation 2 by equation 3 we get,

$(5x+3y=195)-(3x+3y=147)\\2x=48\\x= \frac{48}{2}=24$

Substituting value of x in equation 1 we get.

$x+y=49\\24+y=49\\y=49-24=25$

Hence Lisa's team have played 24 home games and 25 away games.

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Answer:

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Answer:

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