Answer:
The coordinates of 
are 
and 
.
Step-by-step explanation:
Let be 
and 
endpoints of segment AB and a point located 7/10 the way from A to B. Vectorially, we get this formula:
By Linear Algebra we get the location of :
If we know that 
and 
, then:
The coordinates of are and .
Answer:
2a²
Step-by-step explanation:
Pair 'like' terms with 'like' terms, ie numbers go with numbers, and 'a's go with 'a's.
Lets deal with the top of the fraction first:
4ax3a³
Rearrange it so you have numbers beside numbers and 'a's beside 'a's:
(4x3)x(axa³)
12x(a⁴) <em>(because nᵃxnᵇ=nᵃ⁺ᵇ)</em>
12a⁴
Now, instead of (4ax3a³)/6a², we have 12a⁴/6a²
First divide the numbers: 12/6 =2
Now divide the 'a' parts: a⁴/a²=a² <em>(because nᵃ/nᵇ=nᵃ⁻ᵇ)</em>
Now we have 2a²
Point G cannot be a centroid because GE is wider that JG or JG is shorter than GE. So in this diagram GE is wider than JG with 10 cm and 5 cm respectively based on this information Point G cannot be a centroid of triangle HJK. So the answer is point G cannot be a centroid because JG is shorter than GE.
The answer will be 15-4=11
Answer:
12.56637061 ?????
Step-by-step explanation:
