I solved this rational equation by combining expressions and isolating the variable a
a = -2
Answer:
Triangle, pentagon, heptagon, and decagon.
Step-by-step explanation:
REMEMBER THIS:
DECAGON: 10 SIDES
HEPTAGON: 7 SIDES
PENTAGON: 5 SIDES
TRIANGLE: 3 SIDES
EXTRA INFO:
HEXAGON: 6 SIDES
QUADRILATERAL: 4 SIDES
OCTAGON: 8 SIDES
NONAGON: 9 SIDES
Area of a rectangle of length L and width W is A = LW.
Here, A = 60 ft^2 = (12 ft)(2x-3 ft). Let's find the values of x for which the area =60 ft^2, and then the values of x for which the area is greater than 60 ft^2.
60 = 12(2x-3) becomes 5 = 2x - 3 after dividing both sides by 12.
Adding 3 to both sides of this last equation results in 8 = 2x, so x = 4.
Does (12 ft)(2[4 ft] - 3) = 60? Does (12 ft)(5 ft) = 60 sq ft? YES.
The area of this rectangle will be greater than 60 sq ft if x>4 ft. (answer)
Answer:
xy^(2)z^(6)
Step-by-step explanation:
i hope that helps you :)
