The equation of the graphed line 2x + 3y = -6 written in standard form is, $\rm y= -\frac{2}{3}x -2$ and for line 2x + 3y = 6 will be, $\rm y = \frac{-2}{3}x+2$

<h3>What is the equation?</h3>

A mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.

a) 2x + 3y = -6

The line in which the standard form is found as;

Ax + By + C = 0

The typical form of a slope intercept is

y = mx+c

where m denotes the slope and b the line's y-intercept.

$3y= -6-2x\\\\ y=\frac{-6-2x}{3}\\\\ y= -\frac{2}{3}x -2$

To obtain the slope standard form, we rewrite. The obtained equation is in the form of the slope-intercept.

b) 2x + 3y = 6

The line in which the standard form is found as;

Ax + By + C = 0

The typical form of a slope intercept is

y = mx+c

where m denotes the slope and b the line's y-intercept.

$\rm 3y= 6-2x \\\\ y= \frac{6-2x}{3} \\\\ y = \frac{-2}{3}x+2$

Hence, The equation of the graphed line 2x + 3y = -6 written in standard form is, $\rm y= -\frac{2}{3}x -2$

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What is the equation of the graphed line written in standard form?

2x + 3y = -6, 2x + 3y = 6

Summary:

a. The equation of the graphed line 2x + 3y = -6 written in standard form is y= -2/3 x -2.

b. The equation of the graphed line 2x + 3y = 6 written in standard form is y= -2/3 x +2.

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2 years ago