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Dahasolnce [82]
3 years ago
7

Help I don't understand this question.

Mathematics
1 answer:
bija089 [108]3 years ago
5 0

I would go with option choice B.

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I need help!!
Natasha2012 [34]

Answer:

The exact solution is

x = \frac{Ln(60)}{7*Ln(5)}

And the approximation to three decimal places is:

x = 0.363

Step-by-step explanation:

Here we have the equation:

5^{7*x} = 60\\

Now we can remember a property of the natural logarithm function:

Ln(a^n) = n*Ln(a)

Now we can apply the Ln( ) function to both sides of that equation to get:

Ln(5^{7*x}) = Ln(60)

Then we get:

7*x*Ln(5) = Ln(60)

Solving that for x we get:

x = \frac{Ln(60)}{7*Ln(5)}  = 0.363

So the exact solution is:

x = \frac{Ln(60)}{7*Ln(5)}

And the approximation to three decimal places is:

x = 0.363

7 0
3 years ago
Tyronne worked 21 days last month he earned $79 each day how much did tyronne earn last month
krek1111 [17]
The answer is 1,659. hope i helped
3 0
3 years ago
Read 2 more answers
PLEASE HELP! 40 POINTS
Vedmedyk [2.9K]

I'd start with setting up the equations. Calling x the number of students in most popular country 1, and y in country 2.

x + y = 44740

x - y = 5672

now solve for x1 and x2. You can subtract second from first:

0 + 2y = 39068

y = 19534

so

x = 5672 + 19534 = 25206

Add a sentence to answer it in words.

7 0
2 years ago
Read 2 more answers
Brainliest
crimeas [40]

Answer:

2) age increases and the height increases with it

Step-by-step explanation:

<em>As people get older of course they will grow. People don't lose age. And people don't shrink. So not 3 or 4. </em>

<em>There is definitely a relationship. Not 1.</em>

<em />

have a nice day and mark me brainliest! :)

<em> </em>

<em />

4 0
2 years ago
Simplify x+2/x^2+2x-3 divide by x+2/x^2-x
ira [324]

\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}

If x\neq-2, then we can immediately cancel the factors of x+2:

\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}

Factorize the numerator and denominator:

x^2-x=x(x-1)

x^2+2x-3=(x+3)(x-1)

Next, if x\neq1, then

\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}

8 0
3 years ago
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