4 years ago

Help I don't understand this question.

Mathematics

1 answer:

bija089 [108]4 years ago

5 0

I would go with option choice B.

You might be interested in

Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x

Stolb23 [73]

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

$y=a(x-h)^2+k$

(where (h, k) is the vertex)

Given:

vertex = (1, -108)

$\implies y=a(x-1)^2-108$

Given:

y-intercept = (0, -105)

$\implies a(0-1)^2-108=-105$

$\implies a(-1)^2=-105+108$

$\implies a=3$

Therefore:

$\implies y=3(x-1)^2-108$

The x-intercepts are when y = 0

$\implies 3(x-1)^2-108=0$

$\implies 3(x-1)^2=108$

$\implies (x-1)^2=36$

$\implies x-1=\pm \sqrt{36}$

$\implies x=1\pm 6$

$\implies x=7, x=-5$

Therefore, the x-intercepts are (7, 0) and (-5, 0)

7 0

2 years ago

PLZ HELP WILL MARK!!! <3

Digiron [165]

The equation x^2 - 6x + 9 is a perfect square and when factored out it becomes C. ) It is a perfect square (x - 3)^2

7 0

3 years ago

samuel has read 3/6 of his assignment.judy has read 4/8 0f her assingment. their assignments were the same size.which sentence i

ladessa [460]

I'm taking you at your word. I think these sentences are true
because you said them:

-- Samuel has read 3/6 of his assignment.

-- Judy has read 4/8 0f her assingment.

-- Their assignments were the same size.

8 0

3 years ago

If 8 = 27 and F = 540, find ). Round to the nearest tenth.

pychu [463]

Answer: F=160

Step-by-step explanation:

8=27

F = 540

multiply 540 x 8 /27 = F = 160

4 0

3 years ago

Is y=x^3 a solution of the differential equation yy'=x^5+y

shepuryov [24]

No; we have $y=x^3\implies y'=3x^2$ . Substituting these into the DE gives

$3x^5=x^5+x^3$

which reduces to $x^3=0$ , true only for $x=0$ .

3 0

3 years ago