$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
Answer:
The answer to the problem is 125y⁶
1.≤
2.≤
3.≤
4.≤
5.≤
6.≤
Step-by-step explanation:
di po ko sure kung tama po yan
As this value is definite (has an end), it would be considered rational.
