Answer:
i. The ratio of the areas of the two triangles is 5:8.
ii. The area of the larger triangle is 24 in².
Step-by-step explanation:
Let the area of the smaller triangle be represented by
, and that of the larger triangle by
.
Area of a triangle =
x b x h
Where; b is its base and h the height.
Thus,
a. The ratio of the area of the two triangles is:

Area of smaller triangle =
x b x h
=
x 5 x h
=
h
Area of the lager triangle =
x b x h
=
x 8 x h
= 4h
So that;
Ratio = 
= 
The ratio of the areas of the two triangles is 5:8.
b. If the area of the smaller triangle is 15 in², then the area of the larger triangle can be determined as;
= 
= 
5
= 15 x 8
= 120
= 
= 24
The area of the larger triangle is 24 in².
X^2-10x+16= 0
(x-8)(x-2)=0
x = 8 or 2
For this case we have by definition that the area of a parallelogram is given by:

Where:
b: It's the base
h: It's the height
According to the data we have:

Substituting in the formula:

The area of the parallelogram is 
Answer:

X^2+2x^2-5x
((x^2)+2x^2)-5x
Pull the factors out
3x^2-5x=x(3x-5)
x(3x-5)
x(3x-5)*5x^2
5x(3x-5)*x^2
Final
5x^3*(3x-5)