Question

Answer of a ²-10a+16-6b-b^2​

Answer 1

$\quad a^2-10a+16-6b-b^2$

$=(a^2-10a)-(b^2+6b) +16$

$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$

$=(a-5)^2-25-(b+3)^2+9+16$

$=(a-5)^2-(b+3)^2$