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rosijanka [135]
3 years ago
8

Answer of a ²-10a+16-6b-b^2​

Mathematics
1 answer:
german3 years ago
5 0

\quad a^2-10a+16-6b-b^2

$=(a^2-10a)-(b^2+6b) +16$

$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$

$=(a-5)^2-25-(b+3)^2+9+16$

$=(a-5)^2-(b+3)^2$

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Laws involving positive integral exponents to zero & negative integral exponents.
fiasKO [112]

Answer:

  • Both are correct

Step-by-step explanation:

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3 0
2 years ago
As a single logarithm, 2log2 6- log29+ 1/3log2 27 = log2 12.
Ipatiy [6.2K]

Answer:

true

Step-by-step explanation:

2log2 6- log2 9+ 1/3log2 27 =

= log2 6² - log2 9 + log2 27^(1/3)

= log2 36 - log2 9 + log2 3

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The statement is true.

3 0
2 years ago
Which equation is equivalent to logx36=2
coldgirl [10]

Answer:

Which equation is equivalent to logx36=2

Exact Form:

x=10\frac{1}{18}

Decimal Form:

x=1.13646366

8 0
2 years ago
Check my answer please? Get 25 points + Brainliest!!
Zigmanuir [339]
No its sss because you have no given angles only sides 
7 0
3 years ago
Please help me solve this question:)​
omeli [17]

Answer:

The answer would be a=2.

Step-by-step explanation:

Since both sides of the equation are being multiplied by b then you would divide both of them by B. This will just remove the B from the equation entirely and leave you with a=2. I hope that this was helpful.

6 0
3 years ago
Read 2 more answers
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