The formula for depreciation is:

Where x = Initial value,
y= Amount after depreciation.
r= Rate of depreciation,
t = time (in years)
According to given problem,
x = 1040, y= 944 and t = 12 months =1 year.
So, first step is to plug in these values in the above formula, So,

944 = 1040 (1 -r)
 Divide each sides by 1040.
 Divide each sides by 1040.
0.907692308 =1 - r
0.907692308 - 1 = -r Subtract 1 from each sides.
-0.092307692 = -r
So, r = 0.09 or 9%.
Now plug in 0.09 in the above equation to get the depreciation equation. So,

So, 
b) To find the value of the bike after 5 months, 
plug in t = 5 months= 5/12 = 0.41667 years in the above equation of depreciation.
So, 
y = 1040 * 0.961465659
y = 999.9242852
y = 1000 (Rounded to nearest integer).
Hence, the value of the bike after 5 months is $1000.
 
        
             
        
        
        
Just add them together to get the number. 100,000 + 702,083 = 802,083. 802083 is 100,000 more than 702,083.
        
             
        
        
        
Hey there! 
(6^3 * 2^6) / 2^3
= (6 * 6 * 6 * 2 * 2 * 2 * 2 * 2 * 2) / 2 * 2 * 2
= (36 * 6 * 4 * 4 * 4) / 4 * 2
= (216 * 16 * 4) / 8 
= 3,456 * 4 / 8
= 13,824 / 8
= 1,728
Looking for something that gives you the result of: 1,728
Option A. 
12^3
= 12 * 12 * 12
= 144 * 12
= 1,728
Option A. is. possible answer 
Option B. 
6^3
= 6 * 6 * 6
= 36 * 6
= 216
216 ≠ 1,728
Option B. is incorrect
Option C. 
12^6
= 12 * 12 * 12 * 12 * 12 * 12
= 144 * 144 * 144
= 20,736 * 144
= 2,985,984
2,985,984 ≠ 1,728
Option C. is also incorrect 
Option D. 
2^6 * 2^3
= 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2
= 4 * 4 * 4 * 4 * 2
= 16 * 16 * 2
= 256 * 2
= 512
512 ≠ 1,728
Option D. is also incorrect 
Option E. 
2^3 * 3^3
= 2 * 2 * 2 * 3 * 3 * 3
= 4 * 2 * 9 * 3
= 8 * 27
= 216
216 ≠ 1,728
Option E. is also incorrect.
Therefore, the answer should be: 
Option A. 12^3
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
 
        
             
        
        
        
Answer:
substitute 3 as in x:
4(3)-9
= 12-9
= 3
Hope this helped - have a nice day & be safe