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Sav [38]
3 years ago
3

Based on the bar graph shown below, the 25th percentile is located in which interval?

Mathematics
2 answers:
SVEN [57.7K]3 years ago
4 0
0-5 because 25th percentile can also be known as the 1st quartile or the first 25% of it. so since the medium is 8 then it would be the first interval or 0-5.

if i am wrong please let me know.
EastWind [94]3 years ago
4 0

Answer:

B: 6 - 10

Step-by-step explanation:

We have been given a bar graph and we are asked to find 25th percentile in located in which interval.

Let us find total number of data points by adding the heights of all bars together.

\text{Total data points}=5+6+8+10+5

\text{Total data points}=34

Now let us find 25% of 34.

25\%\text{ of }34=\frac{25}{100}\times 34

25\%\text{ of }34=0.25\times 34

25\%\text{ of }34=8.5\approx 9

So 9th data point will be close to 25th percentile as it has 8.5 data points below itself.

Let us see 9th data point will falls in which interval.

We can see from our bar graph that interval 0-5 contains 5 data point and data points between 5 to 11 lies in interval 6-10, therefore, option B is the correct choice as 9 lies between 5 and 11.

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The following table shows the times of trains between Juno and Odiham.
Luba_88 [7]

Answer:

(a) The earliest time that Ferdo can be back at Juno station is 12:15

Step-by-step explanation:

From the given table, we have;

The starting time for train departure from Juno = 07:15

The frequency of train departures from Juno = Every 20 minutes

The time of departure, 't₁' of first train that departs from Juno after 08:30 is given as follows;

The train departure times from Juno = 07:15, 07:35, 07:55, 08:15, 08:35

Therefore;

The time at which the first train departs from Juno after 08:30 = 08:35

The time it takes a train to travel from Juno to Odiham = 0:805 - 07:15 = 50 minutes

The time of arrival of the train Ferdo takes from Juno at Odiham = 08:35 + 50 minutes = 09:25

The number of hours Ferdo spends at Odiham = 2 hours

The time after which Ferdo departs from Odiham = 09:25 + 02:00 = 11:25

The time of departure of the train from Odiham after 11:25 = 08:05 + 20 minutes × 10

Therefore, the time of departure of the train from Odiham after = 11:25

The time it takes on the trip back to Juno from Odiham = 50 minutes

The earliest time that Ferdo can be back at Juno station = 11:25 + 50 minutes = 12:15

8 0
3 years ago
Solve the following system of equations by the substitution method. 5x = y + 6 2x - 3y = 4 What is the value of the y-coordinate
horsena [70]
Why do I have to put 20 characters here?

5 0
3 years ago
Read 2 more answers
A metropolitan transportation authority has set a bus mechanical reliability goal of 3,900 bus miles. Bus mechanical reliability
anygoal [31]

Answer:

a) We need to conduct a hypothesis in order to check if the true mean is more than 3900 bus miles, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3900  

Alternative hypothesis:\mu > 3900  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 3900 bis miles at 10% of signficance.  

b) t=\frac{3950-3900}{\frac{225}{\sqrt{100}}}=2.22    

p_v =P(t_{(99)}>2.22)=0.014  

Step-by-step explanation:

Data given and notation  

\bar X=3950 represent the sample mean

s=225 represent the sample standard deviation

n=100 sample size  

\mu_o =3900 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Assuming this question for part a: Is there evidence that the population mean bus miles is more than 3,700 bus​ miles? (Use a 0.10 level of​significance.) Because is if 3700 not makes sense based on the previous info

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is more than 3900 bus miles, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3900  

Alternative hypothesis:\mu > 3900  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b: Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{3950-3900}{\frac{225}{\sqrt{100}}}=2.22    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=100-1=9  

Since is a one side test the p value would be:  

p_v =P(t_{(99)}>2.22)=0.014  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 3900 bis miles at 10% of signficance.  

3 0
3 years ago
Lateral area and the surface area of each rectangular prism by determining the area of the shape's net
raketka [301]

Answer:

............................................................................

Step-by-step explanation:

5 0
3 years ago
A quarter has a diameter of 2.4 centimeters. What is the area of the coin (round answer to nearest tenth)?
mafiozo [28]

Answer:

4.5

Step-by-step explanation:

The equation of an area of a circle is A=πr² where r is the radius.

The radius is also half the diameter. So the radius of the quarter is 1.2

A=π(1.2)²

A=π(1.44)

A=4.52389

4 0
3 years ago
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