Answer:
y = - 2(x - 1)² + 18
Step-by-step explanation:
- 2x² + 4x + 16 ← factor out - 2 from the first 2 terms
= - 2(x² - 2x) + 16
using the method of completing the square
add/subtract ( half the coefficient of the x- term)² to x² - 2x
= - 2(x² + 2(- 1)x + 1 - 1) + 16
= - 2(x - 1)² + 2 + 16
= - 2(x - 1)² + 18 ← in vertex form
Answer:
The graph of the inverse of h(x) is a vertical line.
Yeah bro just take the 2 and subtract on both side so the y is left alone flip the 100 so now its 001 divide it by 1 and the answer is 007 like the spy.
Answer: Hello mate!
Let's define the variable t as the time, and define t = 0 as the moment when the first skater starts to move:
We know that the speed of the first skater is 8 m/s, and we need to find the position as a function of time, then we need to integrate the velocity over time
if v1(t) = 8m/s
then p1(t) = (8m/s)*t
now we also know that the second skater has a velocity of 9m/s and enters in the frozen lake at t= 10s.
then the velocity of the second skater is: v2(t) = 9m/s, and the position is:
p2(t) = (9m/s)*(t - 10s)
now we want to know how many seconds after the second skater starts are needed for the second skater to overtake the first one.
this is equivalent to see when his positions will be equal.
so p1(t) = p2(t):
(8m/s)*t = (9m/s)(t - 10s) = (9m/s)*t - 90m
(8m/s)*t - (9m/s)*t = -90m
(-1m/s)*t = 90m
t = 90m/(1m/s) = 90s
Then in t = 90 seconds, the second skater will overtake the first one, and knowing that the second skater started at t = 10 seconds; there are 80 seconds after the second skater started needed to overtake the first skater.
If sally has five times more sweets than paul and she gives paul ten, then she probably has 50 sweets, and if you divide 50 by 10 you get five. so Paul would have 5 candies in the first place. im not exactly sure but it’s an idea
