Let's start calculating the value of √(27):
√(27) = √(9*3) = √(9)*√(3) = 3√(3) ≈ 5.196152423
So:
5.196152423 > 5.0
and
5.196152423 < 5.2
Therefore:
5.0 < √(27) < 5.2
<h2>
Answer: Line 1 should be x = y² + 12y NOT (x = y² + 12 x)</h2>
<h3>
Step-by-step explanation:</h3>
solving for the inverse of y = x² + 12x
Line 1: x = y² + 12 x.
Line 2 y² = x - 12 x. <em> </em>
Line 3 is y²= - 11 x.
Line 4 is y = √(- 11x) for x ≥ 0.
The error lies in Line 1. All x's have to be switched with y's and vice versa for the method to work.
As such Line 1 should be x = y² + 12y NOT (x = y² + 12 x)
Since Line one is wrong, it messes with all the other lines.
11.
Given:
Differentiate with respect to x, we get
The given point is (3,9)
Substitute x=3 in the derivative, we get
Hence the slope is 3.
12.
Given:
Differentiate with respect to x, we get
The given point is (0,4)
Substitute x=0 in the derivative, we get
Hence the slope is 0.
∠PXS = (180 - 106) ÷ 2 // isosceles triangle
∠PXS = 37°
∠XQR = 180 - 106 //parallelogram
∠XQR = 74°
∠RXQ = 74° //Isosceles triangle
∠SXR = 180 - 37 - 74 // Adjacent angles on a straight line
∠SXR = 69°
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Answer: ∠SXR = 69°
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