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n200080 [17]
3 years ago
14

Which expression has an estimated product of 60?

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
8 0

Answer:

i think it is (13.2)(4.5)

Step-by-step explanation:

hope it helps

Inessa05 [86]3 years ago
6 0

Answer:

(13.2)(4.5)

Step-by-step explanation:

This is correct because you know that you could round one up, and one down. You know that 12*5 = 60, so you could estimate that these would have a product of 60.

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X + 7y = 21
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x=21−7y?

Step-by-step explanation:

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Tash conducted a survey of the students in her school.
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The total number of students in the school is 750. You can use algebraic equation to calculate the number of the students. Let x be the total number of students in the school. Hope this helps.

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Find the 7th term of the arithmetic sequence 4x + 5, 11x + 9,18x + 13, ...
Svet_ta [14]

Step-by-step explanation:

we see the common difference is

a2-a1 = 11x + 9 - 4x - 5 = 7x + 4

an = an-1 + (7x+4) = a1 + (n-1)×(7x+4)

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a7 = 4x + 5 + 6×(7x +4) = 4x + 5 + 42x + 24 = 46x + 29

5 0
3 years ago
A city council consists of seven Democrats and five Republicans. If a committee of four people is selected, find the probability
Hoochie [10]

Answer:

The probability  of selecting two Democrats and two Republicans is 0.4242.

Step-by-step explanation:

The information provided is as follows:

  • A city council consists of seven Democrats and five Republicans.
  • A committee of four people is selected.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!\times (n-k)!}

Compute the number of ways to select four people as follows:

{12\choose 4}=\frac{12!}{4!\times (12-4)!}=495

Compute the number of ways to selected two Democrats as follows:

{7\choose 2}=\frac{7!}{2!\times (7-2)!}=21

Compute the number of ways to selected two Republicans as follows:

{5\choose 2}=\frac{5!}{2!\times (5-2)!}=10

Then the probability  of selecting two Democrats and two Republicans as follows:

P(\text{2 Democrats and 2 Republicans})=\frac{21\times 10}{495}=0.4242

Thus, the probability  of selecting two Democrats and two Republicans is 0.4242.

6 0
3 years ago
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