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KiRa [710]
3 years ago
6

In a two-digit number, the tens digit is 5 less than the units digit. The number itself is five more than three times the sum of

its digits. What is the number?
Mathematics
2 answers:
irina1246 [14]3 years ago
6 0

Answer:

38

Step-by-step explanation:

Luden [163]3 years ago
5 0

Given:

In a two-digit number, the tens digit is 5 less than the units digit.

The number itself is five more than three times the sum of its digits.

To find:

The number.

Solution:

Let the two digit number is ab. So,

ab=10a+b

Tens digit is 5 less than the units digit.

a=b-5       ...(i)

The number itself is five more than three times the sum of its digits.

10a+b=3(a+b)+5

10a+b=3a+3b+5

10a+b-3a-3b=5

7a-2b=5          ...(ii)

Using (i) and (ii), we get

7(b-5)-2b=5

7b-35-2b=5

5b=5+35

5b=40

b=8

Putting b=8 in (i), we get

a=8-5

a=3

Therefore, the required number is 38.

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