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4 years ago

Hey i really need help, i don’t think i got this right! PLEASE HELP!!!

Mathematics

1 answer:

Crazy boy [7]4 years ago

6 0

It's A multiply the terms with equal exponents by multiplying their bases

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Find <img src="https://tex.z-dn.net/?f=a_%7B1%7D" id="TexFormula1" title="a_{1}" alt="a_{1}" align="absmiddle" class="latex-form

yKpoI14uk [10]

Answer:

$\displaystyle a_{1} = 108$

Step-by-step explanation:

we are given

the sum,common difference and nth term of a geometric sequence

we want to figure out the first term

recall geometric sequence

$\displaystyle S_{ \text{n}} = \frac{ a_{1}(1 - {r}^{n} )}{1 - r}$

we are given that

$S_n=189$
$r=\dfrac{1}{2}$
$n=3$

thus substitute:

$\displaystyle 189= \frac{ a_{1}(1 - {( \frac{1}{2} )}^{3} )}{1 - \frac{1}{2} }$

to figure out $a_1$ we need to figure out the equation

simplify denominator:

$\displaystyle \frac{ a_{1}(1 - {( \frac{1}{2} )}^{3} )}{ \dfrac{1}{2} } = 189$

simplify square:

$\displaystyle \frac{ a_{1}(1 - {( \frac{1}{8} )}^{} )}{ \dfrac{1}{2} } = 189$

simplify substraction:

$\displaystyle \frac{ a_{1} (\frac{7}{8} )}{ \frac{1}{2} } = 189$

simplify complex fraction:

$\displaystyle a_{1} (\frac{7}{8} ) \div { \frac{1}{2} } = 189$

calculate reciprocal:

$\displaystyle a_{1} \frac{7}{8} \times 2 = 189$

reduce fraction:

$\displaystyle a_{1} \frac{7}{4} \ = 189$

multiply both sides by 4/7:

$\displaystyle a_{1} \frac{7}{4} \times \frac{4}{7} \ = 189 \times \frac{4}{7}$

reduce fraction:

$\displaystyle a_{1} = 27\times 4$

simplify multiplication:

$\displaystyle a_{1} = 108$

hence,

$\displaystyle a_{1} = 108$

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3 years ago

Solve the following system of equations<br> 3X +5Y=16<br> 2X+7Y=7

RoseWind [281]

Answer:

equals 56y+3x

Step-by-step explanation:

8 0

3 years ago

How can I solve this problem?

pogonyaev

C is the correct answere

7 0

4 years ago

Find x . round your answer to the nearest tenth of a degree

USPshnik [31]

Answer:

whats the question?

Step-by-step explanation:

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3 years ago

Read 2 more answers

PLEase HeLP I NEeEd it for my progress report please help

vazorg [7]

The answer is A .. you’re welcome ;)

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3 years ago