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3 years ago

Write fifty-seven and one hundred forty-two thousandths in standard form

Mathematics

2 answers:

irina [24]3 years ago

7 0

57.142 is the standard form of the question.

Alina [70]3 years ago

4 0

Six and seven thousand four hundred thirty-three ten-thousandths is written as 6.7433 in standard form.<span> Six is written at the left of the decimal point since the word "and" indicates the separation of a whole number from decimal values. Ten-thousandths specifies the four decimal places after the decimal point.

I hope i helped</span>

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Keegan is priting and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total p

Damm [24]

Complete question is;

Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total profits will be p(x) = -x³ + 4x² + x dollars, in thousands will be earned. How many t-shirts (rounded to the nearest whole number) should he print in order to make maximum profits? What will his profits rounded to the nearest whole dollar be if he prints that number of shirts?

Answer:

Number of t-shirts to make maximum profit = 2790 shirts

Maximum profit = $12,209

Step-by-step explanation:

From the question, we are given that the profit function is;

p(x) = -x³ + 4x² + x

For the maximum value of the profit function,

(dp/dx) = 0 and (d²p/dx²) < 0

Since, p(x) = -x³ + 4x² + x

Then,

(dp/dx) = -3x² + 8x + 1

at maximum point (dp/dx) = 0, thus;

-3x² + 8x + 1 = 0

Solving this using quadratic formula, the roots are;

x = -0.12 or 2.79

Also, (d²p/dx²) = -6x + 8

Now, let's put the roots of x into -6x + 8 and check for maximum value conditon;

at x = -0.12

(d²p/dx²) = -6(0.12) + 8 = 7.28 > 0

At x = 2.79

(d²p/dx²) = -6(2.79) + 8 = -8.74 < 0

Maximum has to be d²p/dx² < 0

So, the one that meets the condition is -8.74 < 0 at x = 2.79

Thus, the maximum of the profit function exists when the number of shirts, x = 2.79 (in thousands) = 2790

Now, the maximum profits that corresponds to this number of t-shirts of 2.79(in thousands) is obtained by putting 2.79 for x in the profit function;

So,

p(2.79) = -(2.79)³ + 4(2.79²) + 2.79

p(x) = -21.7176 + 31.1364 + 2.79

p(x) = 12.2088 (in thousand dollars) ≈ $12,209

6 0

3 years ago

20% of dash is equal to 140M

AlexFokin [52]

ANSWER: The length of the entire dash is 700 meters.

EXPLANATION:

Because 20% of the dash equals 140 meters, we can use a variable to figure out the length of the entire dash.

Let x be the length of the entire dash.

$.2x = 140\\\\x = 700$

The length of the entire dash is 700 meters.

7 0

3 years ago

The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}$

8 0

3 years ago

Read 2 more answers

Rani takes a 40-question test. She answers 5% of the questions incorrectly

Feliz [49]

Answer:

2 Questions.

Step-by-step explanation:

To calculate a how much a percentage is of a number, you multiply the number by the percent.

So, we have the equation:

40 x 0.05 = 2

So, Rani got 2 questions incorrect.

Hope this helps!

5 0

3 years ago

I think it is the 2nd one.

lutik1710 [3]

125 and 8 are perfect cubes.
125 = 5^3
8 = 2^3

125 - 8 = 5^3 - 2^3

3 0

3 years ago