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3 years ago

2xsquered minus 8x minus 24

Mathematics

1 answer:

OlgaM077 [116]3 years ago

6 0

Answer:

x = 6 or x = -2

Step-by-step explanation:

Solve for x:

2 x^2 - 8 x - 24 = 0

The left hand side factors into a product with three terms:

2 (x - 6) (x + 2) = 0

Divide both sides by 2:

(x - 6) (x + 2) = 0

Split into two equations:

x - 6 = 0 or x + 2 = 0

Add 6 to both sides:

x = 6 or x + 2 = 0

Subtract 2 from both sides:

Answer: x = 6 or x = -2

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4 years ago

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Doss [256]

Answer:

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3 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

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3 years ago

On a coordinate plane, 2 lines intersect at (negative 1, 5). Which appears to be the solution to the system of equations shown i

Doss [256]

(-1, 5) because if you plug in -1 to both equations, you should get 5 from both equations. They also cross at that point, making that the solution.

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3 years ago

Read 2 more answers

Number A is 5342. Number B is 11124 greater than A. Number C is 3104 less than B. What is the total value of numbers A,B and C?

Leni [432]

Answer:

B - 16466

C - 13362

total value - 35170

Step-by-step explanation:

to find B add 11124 to 5342 (11124+5342=16466)

to find C subtract 3104 from 16466 (16466-3104=13362)

total value - add them all together

5 0

3 years ago