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REY [17]
4 years ago
11

Is triangle PQR congruent to triangle ACB? If so, which postulate can be used to prove the congruence?

Mathematics
1 answer:
Margaret [11]4 years ago
6 0
You could use b c or d, it depends on what angles and what sides are given

Hope this helps!
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If sin0=2/3 find the values of the other five trigonometric functions of 0.
mamaluj [8]

Answer:

See image

Step-by-step explanation:

It helps a lot to draw a triangle. Sin is OPPOSITE/ HYPOTENUSE. You can use Pythagorean thm to find the third side. Then use cos = ADJ/HYP

tan = OPP/HYP

Then, find reciprocal functions. Reciprocal just means you are flipping the ratios over.

csc = HYP/OPP

sec = HYP/ADJ

tan = ADJ/OPP

The only tricky remaining part is that you cant leave a radical (the square root symbol) on the bottom of a ratio. So you have to fix those. See image.

3 0
3 years ago
Find the value of each variable in the parallelogram?
Ymorist [56]

Answer:

Step-by-step explanation:

In parallelogram opposite angles are equal

6x = 66      {Divide both sides by 6}

x = 66/6

x = 11

20y - 46 = 13y + 10     {Add 46 to both sides}

20y - 46 + 46 = 13y + 10 + 46

             20y   = 13y + 56     {Subtract 13y from both sides}

   20y - 13y    = 13y-13y + 56

              7y    =  56    {Divide both sides by 7}

                y =  56/7

y = 8

8 0
3 years ago
If 3^2x+1=3^x+5 what is the value of x
Diano4ka-milaya [45]
The answer to this question would be 4
4 0
2 years ago
Need help with math homework who can help ?
Softa [21]
What's the problem ?
7 0
3 years ago
Find the slope through each pair of two points. Report answers in simplest form.
yanalaym [24]

Answer:

m=0

Step-by-step explanation:

A general rule to remember is "rise over run" or m= \frac{y_{2} -y_1}{x_2-x_1}

To find the slope between these two pairs of points:

1. Choose one pair of points to be X1 and Y1 (it doesn't matter which)

   In this case, let's use (-11,3) so X1 =-11 and Y1= 3

2. The second pair will be (14,3) so X2 = 14 and Y2=3

3. Applying the equation above:  \frac{y_{2} -y_1}{x_2-x_1}

    It becomes: m= \frac{3-3}{14-(-11)}

                        m = \frac{0}{25}

                        m = 0

4 0
3 years ago
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