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Serggg [28]
3 years ago
8

Simplify |–9.23 – 1.79| – |–7.34 – 2.57|.

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
6 0
[-11.02]-[-9.91]
11.02-9.91=1.11
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Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
katrin2010 [14]

Answer:

Test scores of 10.2 or lower are significantly low.

Test scores of 31.4 or higher are significantly high.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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In this problem, we have that:

\mu = 20.8, \sigma = 5.3

Identify the test scores that are significantly low or significantly high.

Significantly low

Z = -2 and lower.

So the significantly low scores are thoses values that are lower or equal than X when Z = -2. So

Z = \frac{X - \mu}{\sigma}

-2 = \frac{X - 20.8}{5.3}

X - 20.8 = -2*5.3

X = 10.2

Test scores of 10.2 or lower are significantly low.

Significantly high

Z = 2 and higher.

So the significantly high scores are thoses values that are higherr or equal than X when Z = 2. So

Z = \frac{X - \mu}{\sigma}

2 = \frac{X - 20.8}{5.3}

X - 20.8 = 2*5.3

X = 31.4

Test scores of 31.4 or higher are significantly high.

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Step-by-step explanation:

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Answer:

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