Question

Does anyone have the answers for the rest of this or know the answers ?

Answer 1

Answer:

4.

a)  $4x^4-4x^3-16x^2+16x$

b)  $4x^4-4x^3-16x^2+16x$

5. Yes

Step-by-step explanation:

The distributive property is:

$(a+b)(c+d)=ac+ad+bc+bd$

It can be extended to a lot of terms as well.

We will use this to multiply both of the probelms shown.

4 a)

$(4x^2-4x)(x^2-4)=(4x^2)(x^2)-(4)(4x^2)-(4x)(x^2)+(4x)(4)=4x^4-16x^2-4x^3+16x=4x^4-4x^3-16x^2+16x$

The answer is $4x^4-4x^3-16x^2+16x$

4 b)

$(x^2+x-2)(4x^2-8x)=(x^2)(4x^2)-(8x)(x^2)+(x)(4x^2)-(8x)(x)-(2)(4x^2)+(2)(8x)=4x^4-8x^3+4x^3-8x^2-8x^2+16x=4x^4-4x^3-16x^2+16x$

The answer is  $4x^4-4x^3-16x^2+16x$

5. Yes