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xz_007 [3.2K]
3 years ago
15

Two fractions between 2 and 2 1/2

Mathematics
2 answers:
Rudik [331]3 years ago
7 0
2 1/4

2 1/3

These two fractions are both less than 2 1/2 but greater than 2
Serggg [28]3 years ago
3 0

Answer:

2 1/4 and 2 1/3 would work well

Step-by-step explanation:

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Solve for x. 5(x 1) = 4(x 8)
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Asssuming blanks are plus

5(x+1)=4(x+8)

distribute
a(b+c)=ab+ac

5(x+1)=5x+5

4(x+8)=4x+32

5x+5=4x+32
minus 4x from both sides
x+5=32
minus 5 from both sides
x=27
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graph the following systems of equations. which system has no solution? y equals negative x squared, y equals negative 4x minus
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Without a calculator how would you solve this?
mina [271]

Answer:

the largest number that is less than (2+√3)^6 is 2701

Step-by-step explanation:

\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6

=64+192\sqrt{3}+720 +480\sqrt{3} +540+108\sqrt{3} +27\\=1351+780\sqrt{3}

\bigstar\  (2-\sqrt{3} )^6 =\\\\1351-780\sqrt{3}

\bigstar\  \bigstar\  (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}

\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702

\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6

0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0

\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0

\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702

8 0
3 years ago
Kevin's bank offered him a 4.5% interest rate for his mortgage. If he purchases 3 points, what will be his new rate?
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Answer:

The new rate would be  3.75%

Step-by-step explanation:

Purchasing a point simply implies negotiating for a lower rate of interest, which involves paying 1% of the loan in lieu of 1% interest reduction.

A point implies a reduction in interest rate by 0.25% while 3 points would reduce the interest rate by 0.75%(0.25%*3)

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A.

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