The price of one adult ticket is $ 11 and the price of one student ticket is $ 11
<h3><u>Solution:</u></h3>Given that , Mofor’s school is selling tickets to the annual dance competition.
Let the cost of one adult ticket be $m and the cost of one student tickets be $n.
On the first day of ticket sales the school sold 7 adult tickets and 6 tickets for a total of $143.
7m + 6n = 143 ------- eqn (1)
The school took in $187 on the second day by selling 4 adult tickets and 13 student tickets.
4m + 13n = 187 ------ eqn (2)
We have to find the price of an adult ticket and the price of a student ticket.
Now, let us solve the equations.
Multiply eqn 1 by 4
28m + 24n = 572 ----- eqn 3
Multiply eqn 2 by 7
28m + 91n = 1309 ---- eqn 4
Now subtract eqn 4 from eqn 3
28m + 24n = 572
28m + 91n = 1309
(- )--------------------------------------
– 67n = - 737
67n = 737
n = 11
Plug in n = 11 in eqn 1
7m + 66 = 143
7m = 143 – 66
m = 11
Hence, the cost of one adult ticket is $ 11 and cost of one student ticket is $11