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pishuonlain [190]
2 years ago
9

You have 0.2231 grams of an unknown monovalent salt (MCl). You treat it with an excess of AgNO3 and precipitate all the chloride

ion. 0.5471 grams of AgCl precipitates. What is the formula weight and identity of M
Chemistry
1 answer:
ludmilkaskok [199]2 years ago
4 0

Answer:

Formula weight of MCl = 58.55 g/mol

M = Sodium

Explanation:

Calculation of the moles of AgCl as:-

Mass = 0.5471 g

Molar mass of AgCl = 143.32 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{0.5471\ g}{143.32\ g/mol}

Moles= 0.00381\ mol

1 mole of AgCl is produced from 1 mole of MCl

So, moles of MCl = 0.00381 mol

Mass = 0.2231 grams

Molar mass = Mass/Moles = 0.2231 grams/0.00381 mol= 58.55 g/mol

Molar mass of Cl = 35.5 g/mol

Molar mass of M = Molar mass of MCl - Molar mass of Cl = 58.55 g/mol - 35.5 g/mol = 23.05 g/mol

This mass corresponds to sodium.

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vodomira [7]

Answer:

This is very easy Cuz We have 2Na2O We have O2 so thats molecule of Oxygen and its same on product We need to balance Na on start We have 1 on product We have 2 so Just put 2 at start....

Explanation:

Sorry for bad english not my first language :(

2Na+O2-->2Na20

5 0
3 years ago
How many formula units of CaO are in 32.7 g of CaO?
max2010maxim [7]

Answer:

3.51× 10²³ formula units

Explanation:

Given data:

Mass of CaO = 32.7 g

Number of formula units = ?

Solution:

First of all we will calculate the number of moles.

Number of moles = mass/molar mass

Number of moles = 32.7 g/ 56.1 g/mol

Number of moles = 0.583 mol

Number of formula units:

1 mole = 6.022 × 10²³ formula units

0.583 mol ×  6.022 × 10²³ formula units / 1 mol

3.51× 10²³ formula units

The number 6.022 × 10²³ is called Avogadro number.

7 0
2 years ago
Consider the following reaction at equilibrium. What effect will increasing the pressure of the reaction mixture have on the sys
8090 [49]

Answer:

Choice d. No effect will be observed as long as other factors (temperature, in particular) are unchanged.

Explanation:

The equilibrium constant of a reaction does not depend on the pressure. For this particular reaction, the equilibrium quotient is:

Q = \displaystyle \frac{[\mathrm{SO_2\, (g)}]}{[\mathrm{O_2\, (g)}]}.

Note that the two sides of this balanced equation contain an equal number of gaseous particles. Indeed, both [\mathrm{SO_2\, (g)}] and [\mathrm{O_2\, (g)}] will increase if the pressure is increased through compression. However, because \rm SO_2\, (g) and \rm O_2\, (g) have the same coefficients in the equation, their concentrations are raised to the same power in the equilibrium quotient Q.

As a result, the increase in pressure will have no impact on the value of Q\!. If the system was already at equilibrium, it will continue to be at an equilibrium even after the change to its pressure. Therefore, no overall effect on the equilibrium position should be visible.

8 0
2 years ago
How is density different from weight and mass?
defon

Hello there!

How is density different from weight and mass you say? It's simple!

1. Unlike weight, density is composed of mass and volume.

2. By dividing the mass over the volume, you can determine an object's density, while weight is the product of mass and gravity.

Hope this helps :) if so, can I get Brainliest?

5 0
1 year ago
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Your answer is C 
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