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pishuonlain [190]
3 years ago
9

You have 0.2231 grams of an unknown monovalent salt (MCl). You treat it with an excess of AgNO3 and precipitate all the chloride

ion. 0.5471 grams of AgCl precipitates. What is the formula weight and identity of M
Chemistry
1 answer:
ludmilkaskok [199]3 years ago
4 0

Answer:

Formula weight of MCl = 58.55 g/mol

M = Sodium

Explanation:

Calculation of the moles of AgCl as:-

Mass = 0.5471 g

Molar mass of AgCl = 143.32 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{0.5471\ g}{143.32\ g/mol}

Moles= 0.00381\ mol

1 mole of AgCl is produced from 1 mole of MCl

So, moles of MCl = 0.00381 mol

Mass = 0.2231 grams

Molar mass = Mass/Moles = 0.2231 grams/0.00381 mol= 58.55 g/mol

Molar mass of Cl = 35.5 g/mol

Molar mass of M = Molar mass of MCl - Molar mass of Cl = 58.55 g/mol - 35.5 g/mol = 23.05 g/mol

This mass corresponds to sodium.

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Table Giving Answer

Element Atomic mass % Amount

Mg_24     24                79    18.96

Mg_25 25                10    2.5

Mg_26 26                11   2.86

   

Total                     24.32

Discussion

The method of calculation for this table, which was done in Excel (a spread sheet) is shown below. Assume that there is 100 grams of material of "pure" magnesium. What is it's mass?

<em><u>Sample  Calculation</u></em>

The the sample atomic mass = 24

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Mass = 79% * 24

Mass = (79/100) * 24

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<em><u>Note</u></em>

The other two elements are found exactly the same as the sample calculation.

Then all you do is add the 3 masses together.

Answer

The mass of Mg to 1 decimal place is 24.3 <<<< Answer.


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