The slope of a line perpendicular to the
graph of the equation 5x - 3y = 2 is -3/5.
<h3>How to find the slope of a line?</h3>
given that the equation is 5x - 3y = 2.
now write the equation in standard form y = mx + b
then -3y = 2 - 5x
y = -2/3 + 5x/3
y = 5/3x - 2/3
m 1*m 2 = - 1 is the formula for the slopes from a pair of perpendicular lines. where the slopes of the lines are m 1 and m 2.
Here m1 = 5/3 and m2 = -3/5.
Hence,the slope of a line perpendicular to the
graph of the equation 5x - 3y = 2 is -3/5.
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The answer is y=2x+5
To get it use point slope by taking two points and solving .
Slope formula
M= y2-y1/x2-x1
With two points
(0,5)(-5,-5)
M= -5-5/-5-0
M= -10/-5
M=2
2 is slope
Now get one of the points
(0,5) And slope to create equation y=mx+b . Now find b
5=2(0)+b
5=b
So now you can put it all together
Y= 2x+5
Answer:
C
Step-by-step explanation:
C is the answer because a1=7 , d=-4 and so it's
an=an+(n-1)d
In a full rotation, 360°, a point on the edge of a gear would travel a distance equal to its circumference. The circumference of a circle is:
C=2πr, and since we are only traveling 150°, we need to set up an appropriate ratio for circumference to the distance the point travels:
d/C=150/360
d=5C/12 and since C=2πr
d=10πr/12
d=5πr/12, and since r=4in
d=5*4π/12 in
d=20π/12 in
d=5π/3 in
d≈5.24 in (to nearest hundredth of an inch)
Answer:
3
Step-by-step explanation:
In a slope intercept linear equation, the slope is always the number in front of the x value in an equation like y = mx + b.
So the slope is the 3 in front of the x value.
