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Aleonysh [2.5K]
3 years ago
12

Cómo se ase este diagrama

Mathematics
1 answer:
Paul [167]3 years ago
5 0
Como se ase ate tiki hyev
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If Chris has 2 times as many nickels as quarters and they have a combined value of 210 cents, how many of each coin does he have
BlackZzzverrR [31]
Im pretty sure she has 6 quarters and 12 nickels since it it twice as much.

$0.25 x 6 =150

$0.5 x 12 =60

total = 210
8 0
3 years ago
Pls help <br><br> Thank you ❤️
nikdorinn [45]

Answer:

the difference is 78

the avg drop is 3 degrees per kilometer

Step-by-step explanation:

Hope this helps

4 0
3 years ago
Answer number 3<br><br><br> quickly i am in a rush
SVEN [57.7K]

Answ34.5

Step-by-step explanation:

8 0
2 years ago
Please help the problem is in the picture provided below.
Nadya [2.5K]

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sorry I don't know

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4 0
2 years ago
Read 2 more answers
10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the
Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

H_0: \mu = 0

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

H_1: \mu > 0

<h3>What is the test statistic?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

In this problem, the parameters are given as follows:

\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50.

Hence, the test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by t^{\ast} = 2.4.

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0
1 year ago
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