Since y is the suqraed term, it opens left or right in this form it is (y-k)²=4p(x-h)
(h,k) is the vertex if p is negative then it opens to the left and directix is to the right of the vertex if p is positve then it opens to the right and directix is to the left of the vertex p is the distance from vertex to directix
so (y-0)²=4(-6)(x-0) the vertex is (0,0) -6 is negative so vertex is (0,0) directix is 6 unts to the right of (0,0) or at x=6