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blondinia [14]
3 years ago
8

-5p greater than -30 solve the inequality

Mathematics
1 answer:
Sphinxa [80]3 years ago
4 0
-5p > -30
Divide both sides by -5 so that the only thing remaing on the left side is the variable p.
Final Answer: p>6
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Convert 91007500 to scientific notation
sesenic [268]
Scientific notation is a number greater than 0 and less than 10 multiplied by 10 to a power. The expression will be equal to the number given.
91007500
We move the decimal place first so that the number is within our range:
9.1007500
Then we count how many places we moved the decimal. In this case we moved it to the left 7 times, so our exponent of 10 will be 7
Therefore in scientific notation it is 9.1007500 x 10^7
Some teachers prefer to have scientific notation rounded off to the nearest 10th place, so that would be:
9.1 x 10^7
8 0
2 years ago
Given: Parallelogram LMNO; MO ⊥ LN Prove: LMNO is a rhombus. Parallelogram L M N O is shown. Diagonals are drawn from point L to
BaLLatris [955]

Answer: LMNO is a rhombus

Step-by-step explanation: Since LMNO= Mo x LN, Point M=LM x ON, given these circumstances, we know that LMNO is a rhombus from the sides and angles equation.

3 0
3 years ago
Read 2 more answers
Which equation would have real zero(s) corresponding to the x-intercept(s) of the graph below?
MA_775_DIABLO [31]

Answer:

Choice A.

y =  -  {2}^{x}  + 4

Step-by-step explanation:

Use graphing calculator

7 0
2 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
2 years ago
Pllsssss help <br> Explanation plsss
aleksklad [387]

Answer:

x = 17

Step-by-step explanation:

8x - 9 + 53 = 180 (collect like terms)

8x + 44 = 180 (subtract 44 on both sides)

8x = 136 (divide by 8 on each side)

x = 17

HOpe this helps!!

5 0
3 years ago
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