Answer:
The probability that 8 mice are required is 0.2428.
Step-by-step explanation:
Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.
To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?
Solution :
Applying binomial distribution,

Where, p is the probability of success 
q is the probability of failure q=1-p, 
n is total number of trials n=8
r=3
Substitute the values,




Therefore, the probability that 8 mice are required is 0.2428.
Answer:
A = 143.2
Step-by-step explanation:
A= πr² = π(6.75)² =
× 45.5625 = 143.196 ≈143.2
Hi there!
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I believe your answer is:
(-3, -1) and (1, 3)
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Here’s why:
- I have graphed the two equations given on a graphing program.
- When graphed, they pass at points (-3, -1) and (1,3). Therefore, they are the solutions to the system.
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See the graph attached.
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Hope this helps you. I apologize if it’s incorrect.
Answer:
Is this a question. If so I will change my answer
Step-by-step explanation: