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ANTONII [103]
4 years ago
9

1.I am equivalent to 1/2

Mathematics
1 answer:
padilas [110]4 years ago
4 0

Answer:

1/5

Step-by-step explanation:

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6 qts equals ? pints 8 qts equals ? gallons and 48 fl oz equals ? cups
nikdorinn [45]
6 quarts equals 12 pints
8 quarts equals 2 gallons
48 fl oz equals 6 cups
8 0
3 years ago
Read 2 more answers
7<br> a. 49<br> b. 98<br> c. 12<br> 14<br><br><br> I need the area!!
sp2606 [1]

Answer:

49

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh

A = 1/2 (14)*7

A =49

3 0
3 years ago
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Which of the following is a non-prime factor of 70? Select one: A. 5 B. 7 C. 10 D. 15
Umnica [9.8K]

Answer:

C. 10

Step-by-step explanation:

by deduction, 5 and 7 are prime numbers and 15 is not a multiple of 70, therefore the answer must be 10 as it is a non-prime number and is a factor of 70 (I.e. 10 and 7)

5 0
3 years ago
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A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.
tatyana61 [14]

Answer:

(a)g(n)=0.05\cdot 2^n

(b)g^{-1}(n)=\log_{2}20g(n)

(c)43 times

Step-by-step explanation:

<u>Part A</u>

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n

<u>Part B</u>

<u />g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)<u />

<u />

<u>Part C</u>

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

3 0
3 years ago
Which equation represents a population of 210 animals that decreases at an annual rate of 14%
soldi70 [24.7K]

Answer:

The equation i.e. used to denote the population after x years is:

P(x) = 490(1 + 0.200 to the power of x

Step-by-step explanation:

This problem could be modeled with the help of a exponential function.

The exponential function is given by:

P(x) = ab to the power of x

where a is the initial value.

and b=1+r where r is the rate of increase or decrease.

Here the initial population of the animals are given by: 490

i.e. a=490

Also, the rate of increase is: 20%

i.e. r=20%

i.e. r=0.20

Hence, the population function i.e. the population of the animals after x years is:

P(x) = 490(1 + 0.200 to the power of x

6 0
3 years ago
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