1.I am equivalent to 1/2

Julia makes friendship bracelets. She was recently given nine bracelets from different people. At Christmas, she plans to give a

sergey [27]

Answer:

The number of bracelets with she start are 48.

Step-by-step explanation:

Given:

Julia was recently given 9 bracelets. She plans to give 1/3 of her bracelets. She will be left with 23.

Now, we need to find with how many did she start.

Let the bracelets with she start be $x$ .

She plans to give $\frac{1}{3}ofx$ = $\frac{x}{3}$ .

According to question:

$x-9-\frac{x}{3}=23$

On solving the equation:

$\frac{3x-27-x}{3} =23$

Multiplying both sides by 3 we get:

$3x-27-x=69$

$2x-27=69$

Adding both sides by 27 and then dividing by 2 we get:

$x=48$

Therefore, the number of bracelets with she start are 48.

6 0

3 years ago

In 1 mile she counts 33 post if they are spaced evenly how many feet apart are they

Tcecarenko [31]

They are spaced about 0.030 miles apart or 53.33 yards apart. Just divide 1 mile by 33 and get your answer. :) Hope I helped!

6 0

3 years ago

Divide using polynomial long division (3x2 - 11x - 26) = (x - 5)

julsineya [31]

Answer:

.

Step-by-step explanation:

8 0

3 years ago

There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl

Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0

3 years ago

Find the measure for angle f 46 34 122 58

xxMikexx [17]

Answer:

$\angle f = 122\degree$

Step-by-step explanation:

$\angle d = 58\degree$ (vertical angles)

$\angle f+\angle d= 180\degree$

(Interior angles on the same side of transversal)

$\angle f+ 58\degree = 180\degree$

$\angle f = 180\degree-58\degree$

$\huge \orange {\boxed {\angle f = 122\degree}}$

5 0

3 years ago