Any times you see the phrase: "Rate of Change", or even sometimes just the word "Rate" think slope.
The word slope is just a fancy word that means the rate of change.
Rate of Change is just a fancy phrase meaning how much does something change over some amount of time.
So in this case our rate of change will have the units of inches per year.
Let's get to the problem at hand!
We'll need to find slope / the rate of change (the two are interchangeable with each other).
Let's go over the formula for slope:
m = (y2 - y1) / (x2 - x1)
First we will need to label each of the "coordinated points (the two numbers that go together in a pair)" with either (x1,y1) or (x2,y2).
A Giant Red Oak's diameter in 1965 was 248 inches. Keep in mind time is ALWAYS going to be X in rate of change problems (and most all problems for that matter).
(1965,248)
(X1,Y2)
(2005,251)
(X2,Y2)
Plug in the values into the equation!
m = (y2 - y1) / (x2 - x1)
m = (251 - 248) / (2005 - 1965)
m = (3) / (40)
Type that into a calculator to get a decimal value over 1.
m = 0.075 inches per 1 year.
Or...
m = 0.075in / 1 year
Answer:
31
Step-by-step explanation:
(24/3)+(7x2)-(15/5)+(6*2)
8+(7x2)-(15/5)+(6*2)
8+14-(15/5)+(6*2)
8+14-3+(6*2)
8+14-3+12
22-3+12
19+12
31
Sorry if I did my math wrong :)
Answer:
Check pdf
Step-by-step explanation:
Answer: The answer is 13/54
Step-by-step explanation:
52 people out of 216 do not want the stadium, so the fraction would be 52/216. 52/216 simplified would be 13/54.
Answer:
Anthony paid for 7 days of parking.
Step-by-step explanation:
From the information given, the cost of parking a motor home in a state park would be equal to the one time fee plus the result of multiplying the daily rate for the number of days:
c=180+55x, where c is the cost of parking the motor home and x is the number of days.
Now, you can replace c with 565 that is the amount Anthony prepaid and you can solve for x to be able to find the number of days he paid for:
565=180+55x
565-180=55x
385=55x
x=385/55
x=7
According to this, Anthony paid for 7 days of parking.