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oksian1 [2.3K]
3 years ago
10

Is 9 over 10 terminating or repeating

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
7 0
It is terminating. 9 ÷ 10= 0.9

Hoped this helped.

~Bob Ross®
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There are 7 people who play brass
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MAVERICK [17]

I believe the answer is $8.76!

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3 years ago
A random sample of 64 students at a university showed an average age of 20 years and a sample standard deviation of 4 years. The
adelina 88 [10]

Answer:

The 90%  confidence level is  19.15<  L  <   20.85

Step-by-step explanation:

From the question we are told that

     The sample size is  n =  64

     The mean age is  \= x  =  20  \ years

      The standard deviation  is   \sigma  =  4 \ years

 

Generally  the degree of freedom for this data set is mathematically represented as

        df  = n -  1

substituting values

        df  = 64 -  1

        df  = 63

Given that the level of confidence is  90%  the significance level is mathematically evaluated as

          \alpha  =  100 - 90

         \alpha  =10 %  

         \alpha   = 0.10

Now   \frac{\alpha }{2}  =  \frac{0.10}{2}  = 0.05

Since we are considering a on tail experiment

The  critical value for half of  this significance level at the calculated  degree of freedom is obtained from the critical value table as

           t_{df, \frac{ \alpha}{2}   } = t_{63,  0.05   } =  1.669

   The margin for error is mathematically represented as

          MOE  =  t_{df ,  \frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

substituting values  

          MOE  = 1.699  *   \frac{4 }{\sqrt{64} }

         MOE  = 0.85

he 90% confidence interval for the true average age of all students in the university is evaluated as follows

           \= x - MOE  <  L  <  \= x  + E

substituting values  

         20  - 0. 85 <  L  <   20  + 0.85

         19.15<  L  <   20.85

4 0
3 years ago
~And ~ again...~
Mariulka [41]
D. 16pi ft

8 x 2 = 16 x pi = 16pi
3 0
3 years ago
How do I solve this?
Doss [256]

Start with

4i\sqrt{5}

Since square root and square are two opposite operations, we have

4i = \sqrt{(4i)^2} = \sqrt{-16}

So, we have

4i\sqrt{5} = \sqrt{-16}\cdot\sqrt{5}

Use the rule \sqrt{a}\cdot\sqrt{b}=\sqrt{ab} to conclude

\sqrt{-16}\cdot\sqrt{5} = \sqrt{-16\cdot 5} = \sqrt{-80}

7 0
4 years ago
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