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Molodets [167]
3 years ago
10

Which inequality is true if p = 3.4? A. 3p < 10.2 B. 13.6 < 3.9p C. 5p > 17.1 D. 8.5 > 2.5p

Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0

Answer:

A. 3p < 10.2

Step-by-step explanation:

The answer is the above mentioned because by solving 3p < 10.2, you divide both side by the number attached to the variable 'p'. ie 3p/3 < 10.2/3 and that gives you p < 10.2/3. 10.2/ 3 gives you 3.4. ie p<3.4. Therefore making the answer A. 3p<10.2

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The line represented by the equation y=-3/2x is translated up 3 units.
kati45 [8]

Answer:

(0, 3)

Step-by-step explanation:

     In slope intercept form, the y-intercept is the "b" or, in an example:

           y = mx + b

     - m is the slope

     - b is the y-intercept

     In our first equation, the b is 0 (y=-3/2x, there is no +/- b, so it is 0). If we add positive 3 (up 3 units) then the y-intercept will be 3. This, in a point, is shown with (0, 3) because the y-intercept is where the line hits the y-axis when x is 0.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

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8 0
3 years ago
Is the following relation a function? {(0.3, 0.6), (0.4, 0.8), (0.3, 0.7), (0.5, 0.5)}
Readme [11.4K]

Answer:

no

Step-by-step explanation:

To be a function, the x values must correspond to one and only one y value.

In the coordinates given, (0.3, 0.6) and (0.3, 0.7) have the same x- value.

That means that they cannot be a function.

7 0
4 years ago
Which statements describe the graph of y = Negative RootIndex 3 StartRoot x minus 1 EndRoot + 2? Select three options.
SOVA2 [1]

Answer:

The graph has a domain of all real numbers.

The graph has a y-intercept at (0,1).

The graph has an x-intercept at (-7,0).

Step-by-step explanation:

Given: The graph is y=\sqrt[3]{x-1}+2

The domain of a function is a set of input values for which the function is real and defined.

Thus, the graph has a domain of (-\infty, \infty).

To find the y-intercept:  To find the y-intercept, substitute x=0 in y=\sqrt[3]{x-1}+2.

\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}

Thus, the y-intercept is (0,1)

To find the x-intercept: To find the x-intercept, substitute y=0 in y=\sqrt[3]{x-1}+2 .

\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}

Thus, the x-intercept is (-7,0)

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