Answer:
Yes, △ABC ∼ △FED by AA postulate.
Step-by-step explanation:
Given:
Two triangles ABC and FED.
m∠A = m∠B
m∠C = m∠A + 30°
m∠E = m∠F = 
m∠D =
°.
Now, let m∠A = m∠B = 
So, m∠C = m∠A + 30° = 
Now, sum of all interior angles of a triangle is 180°. Therefore,
m∠A + m∠B + m∠C = 180

Therefore, m∠A = 50°, m∠B = 50° and m∠C = m∠A + 30° = 50 + 30 = 80°.
Now, consider triangle FED,
m∠D+ m∠E + m∠F = 180

Therefore, m∠F = 50°
m∠E = 50° and
m∠D = 
So, both the triangles have congruent corresponding angle measures.
m∠A = m∠F = 50°
m∠B = m∠E = 50°
m∠C = m∠D = 80°
Therefore, the two triangles are similar by AA postulate.
Answer:
(-1,8)
(4,-27)
Step-by-step explanation:
y+7x=1
Let x = -1 and find y
y+7(-1)=1
y -7 =1
Add 7 to each side
y-7+7 = 1+7
y = 8
(-1,8)
Let x = 4 and find y
y+7(4)=1
y +28 =1
Subtract 28 from each side
y+28-28 = 1-28
y = -27
(4,-27)
Step-by-step explanation:
the process is show in the above picture.