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fiasKO [112]
2 years ago
8

Find the two solutions of x/3 -1 < 3x/4​

Mathematics
1 answer:
zheka24 [161]2 years ago
5 0

x >  - 2 \frac{2}{5}  \\     \\ x >  - 2.4

<h2><em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>!</u></em><em><u> </u></em></h2><h3><em><u>#</u></em><em><u>c</u></em><em><u>a</u></em><em><u>r</u></em><em><u>r</u></em><em><u>y</u></em><em><u> </u></em><em><u>on </u></em><em><u>learning</u></em></h3>

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What is -3 - 9n= 42 I can’t be negative
maw [93]

If you were to correctly simplify this equation, the answer would be a negative.

The answer is: n = -5

Here's how I got my answer:

Step 1: Add 3 to both sides. Which leaves us with -9n=42+3

Step 2: Simplify 42+3 to 45. Which leaves us with -9n = 45

Step 3: Divide both sides by -9. Which leaves us with n = -45/9

Step 4: Simplify -45/9, to get your answer, n = -5.

4 0
4 years ago
Definition: The ___ tells how fast a line rises or falls between any two points on that line. Algebraically it is expressed as (
liraira [26]
The answer is the slope which is rise over run.
7 0
3 years ago
Read 2 more answers
Please show me how to solve the initial value problem <br> y'=tanx y(pi/4)=3
AlexFokin [52]
The ODE is separable, i.e. you can write

\dfrac{\mathrm dy}{\mathrm dx}=\tan x\iff\mathrm dy=\tan x\,\mathrm dx

Integrating both sides gives the general solution.

\displaystyle\int\mathrm dy=\int\tan x\,\mathrm dx
y=-\ln|\cos x|+C

Given that y\left(\dfrac\pi4\right)=3, we have

3=-\ln\left|\cos\dfrac\pi4\right|+C
3=-\ln\dfrac1{\sqrt2}+C
3-\ln\sqrt2=C


and so the particular solution to the IVP is

y=-\ln|\cos x|+3-\ln\sqrt2
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4 0
3 years ago
-9&lt;2x+1&lt;5<br><br> A. -5 B. -4 C. 4&gt;x&gt;-3<br> D. 5&gt;x&gt;-2
Lilit [14]

Answer:

B

Step-by-step explanation:

1.

- 9 < 2x + 1

- 10 < 2x

X > - 5

2.

2x + 1 < 5

2x < 4

X < 2

4 0
2 years ago
The point P=\left(-\frac{\sqrt{33}}{7},\,\, y\right)P=(− 7 33 ​ ​ ,y) lies on the unit circle shown below. What is the value of
kifflom [539]

Answer:

y = √-1040/7

Step-by-step explanation:

The equation of a unit circle is expressed as;

x²+y² = 1

Given the coordinate of P = (-33/7, y)

Substitute the coordinate into the give expression and find y;

(-33/7)²+y² = 1

Expand

y² = 1-(-33/7)²

According to difference of two square

y² = (1+(-33/7))1-(-33/7))

y² = (1-33/7)(1+33/7)

y² = -26/7(40/7)

y² = -1040/49

y= √-1040/49

y = √-1040/√49

y = √-1040/7

Hence the value of y is y = √-1040/7

4 0
3 years ago
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