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2 years ago

Find the two solutions of x/3 -1 < 3x/4

Mathematics

1 answer:

zheka24 [161]2 years ago

5 0

$x > - 2 \frac{2}{5} \\ \\ x > - 2.4$

<h2>hope it helps! </h2><h3>#carry on learning</h3>

You might be interested in

Is 5:2 the same as 2:5

Neporo4naja [7]

Answer:

It is not the same

Step-by-step explanation:

Is 5/2 greater than 2/5? Is 5/2 bigger than 2/5? Is 5/2 larger than 2/5? These are all the same questions with one answer.

When comparing fractions such as 5/2 and 2/5, you could also convert the fractions (if necessary) so they have the same denominator and then compare which numerator is larger.

To get the answer, we first convert each fraction into decimal numbers. We do this by dividing the numerator by the denominator for each fraction as illustrated below: 5/2 = 2.5

2/5 = 0.4 Therefore, 5/2 is greater than 2/5 and the answer to the question "Is 5/2 greater than 2/5?" is yes.

6 0

3 years ago

Read 2 more answers

Mrs. Nestler enjoys listening to classical music. She has the following audio CDs by her favorite composers in her collection: 4

ivolga24 [154]

Answer:

10.55% probability

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the CDs are chosen is not important. So we use the combinations formula to solve this question.

1 Bach CD, from a set of 4.

1 Beethoven CD, from a set of 6.

1 Brahms CD, from a set of 3.

1 Handel CD, from a set of 2.

So, D=144

4 CDs from a set of 4+6+3+2 = 15.

So, T= 1365

p= D/T= 144/1365 = 0.1055

10.55% probability that she will choose one by each composer

4 0

3 years ago

Consider the probability that greater than 96 out of 153 DVDs will work correctly. Assume the probability that a given DVD will

ICE Princess25 [194]

Answer:

0.3594 = 35.94% probability that greater than 96 out of 153 DVDs will work correctly.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .