Answer: First option 13
Solution
If ABCD is a rhombus, the diagonals must be perpendicular, then the angle (5x+25)° must be a right angle (90°):
(5x+25)°=90°
5x+25=90
Solving for x: Subtracting 25 both sides of the equation:
5x+25-25=90-25
Subtracting:
5x=65
Dividing both sides of the equation by 5:
5x/5=65/5
Dividing:
x=13
Answer: The value of x must be 13
Answer:
Segment EF is twice as long as segment AB.
The length of segment EH is 16 units.
Step-by-step explanation:
its
Part 1:all triangles have a measure of 180 degrees
so, 3(x+2)+35+52=180
add 35 and 52; 3(x+2) +87=180
subtract 87 from both sides; 3(x+2)= 93
divide both sides by 3; x+2=31
subtract both sides by 2; x=29
Part 2: since 3(x+2) =93, angle C is 93 degrees
Answer:
here you have to use the law of sines
let tree make an angle of 83 deg.with the ground. (YZ)angle ZYX = 83deg
he walks 100 feet away from tree to point X (YX)angle YXZ= 33 deg
so remaining angle YZX = 64 deg
triangle YXZ is formed
sin A /a = sin B /b = sin C /c
Sin YZX/100 = sin YXZ/ YZ
sin 64/100 = sin 33/YZ
100 * sin 33/sin 64 = YZ
100*0.54/0.898= YZ
YZ= 60.13 feet the height of the tree
Step-by-step explanation:
