Answer:
261 km
Step-by-step explanation:
given,s=constant
d1/T1=d2/T2
d1=90km,t1=50 min
d2=? ,t2=(120+25)min
=145min
therefore,d2=(90×145)/50
=261 km
Let x = speed of the first car
the second car is 12 km slower so the seconds car speed is x-12
they each drove 2 hours so 1st car = 2x
2nd car = 2(x-12)
they drove 360 km
so you have 2x + 2(x-12) = 360
solve for x
2x+2(x-12) = 360
2x + 2x-24 = 360
4x-24 = 360
4x = 384
x = 384/4
x = 96
1st car drove at 96 km per hour
slower car drove at 96-12 = 84 km per hour
Answer:
50%: day 13
100%: day 26
Step-by-step explanation:
We are given two days and the amount of the moon that is illuminated. The two days are points on a straight line.
(1, 0.02), (2, 0.06)
y = mx + b
m = (0.06 - 0.02)/(2 - 1) = 0.04
y = 0.04x + b
0.02 = 0.04(1) + b
b = -0.02
y = 0.04x - 0.02
We want y = 50% = 0.5
0.04x - 0.02 = 0.5
0.04x = 0.52
x = 13
y = 100% = 1
0.04x - 0.02 = 1
0.04x = 1.02
x = 25.5
Answer:
12.4
Step-by-step explanation:
The distance between (7,21) and (-5,18)
d =sqrt( (-5-7)^2 + (18-21)^2)
= sqrt(( -12)^2 + (-3)^2)
= sqrt(144+9)
= sqrt(153)
=12.36931688
To the nearest tenth
12.4
<span><span><span><span>4x = 16</span><span>log 4x = log 16</span> </span><span>Take the common logarithm of both sides. (Remember, when no base is written, that means the base is 10.) What can you do with that new equation?</span></span><span> <span><span>log 4x = log 16</span>x<span> log 4 = log 16</span></span>Use the power property of logarithms to simplify the logarithm on the left side of the equation.</span><span> <span>x<span> log 4 = log 16</span></span><span>Remember that log 4 is a number. You can divide both sides of the equation by log 4 to get x by itself.</span></span><span>Answer<span>Use a calculator to evaluate the logarithms and the quotient.</span></span></span>
