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ratelena [41]
3 years ago
6

What is the difference of: (-3.4x+4.7)-(3+2.9x)

Mathematics
2 answers:
WINSTONCH [101]3 years ago
5 0

(-3.4x+4.7)-(3+2.9x)=

distribute

-3.4x +4.7 - 3 -2.9x=

combine like terms

-3.4x -2.9x +4.7 -3

-6.3x+1.7

Mariulka [41]3 years ago
5 0

First you need to remove the parenthesis ,and then combine or put together the like terms .Then after doing this you can find the difference:

-3.4x+4.7 - 3+2.9x

Next Simplify : -3.4x+4.7-3-2.9x:

You'll get a final answer of  : --6.3x+1.7

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Answer:

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3 years ago
A Bernoulli differential equation is one of the form dxdy+P(x)y=Q(x)yn Observe that, if n=0 or 1, the Bernoulli equation is line
aleksandr82 [10.1K]

It's unclear whether the ODE is

xy'+y=4xy^2

or

xy+y'=4xy^2

If the first case, then divide through both sides by y^2 to get

xy^{-2}y'+y^{-1}=4x

then substitute z=y^{-1}, so that z'=-y^{-2}y'. Then

-xz'+z=4x\implies-\dfrac1xz'+\dfrac1{x^2}z=\left(-\dfrac1xz\right)'=\dfrac4x

\implies-\dfrac1xz=\displaystyle\int\frac4x\,\mathrm dx

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\implies\boxed{y=\dfrac1{Cx-4x\ln|x|}}

If the second, then dividing through by y^2 gives

xy^{-1}+y^{-2}y'=4x

The same substitution as before gives

xz-z'=4x\implies e^{-x^2/2}z'-xe^{-x^2/2}z=\left(e^{-x^2/2}z\right)'=-4xe^{-x^2/2}

\implies e^{-x^2/2}z=\displaystyle-4\int xe^{-x^2/2}\,\mathrm dx

\implies z=4+Ce^{x^2/2}

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5 0
3 years ago
Use a sum or difference formula to find the exact value of the trigonometric function. sine startfraction 7 pi over 12 endfracti
VARVARA [1.3K]
We have that
<span>sin (7π/12)=?

we know that
</span>7π/12=(π/4+π/3)
and 
<span><span>sin<span>(A+B)</span>=sin<span>(A)</span>cos<span>(B)</span>+cos<span>(A)</span>sin<span>(B)

then
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the answer is (√2+√6)/4

</span>
4 0
3 years ago
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