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guajiro [1.7K]
3 years ago
8

The difference of seventeen and three

Mathematics
1 answer:
kramer3 years ago
5 0
Fourteen is the correct answer
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There is a bag filled with 3 blue and 4 red marbles.
tresset_1 [31]

Using the hypergeometric distribution, it is found that there is a 0.4286 = 42.86% probability of getting 2 of the same colour.

The marbles are chosen without replacement, hence the <em>hypergeometric </em>distribution is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There is a total of 3 + 4 = 7 marbles, hence N = 7.
  • Of those, 3 are blue, hence k = 3.
  • 2 marbles will be taken, hence n = 2.

The probability of getting 2 of the same colour is the sum of P(X = 0), which is both red, with P(X = 2), which is both blue, then:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,7,2,3) = \frac{C_{3,0}C_{4,2}}{C_{7,2}} = 0.2857

P(X = 2) = h(2,7,2,3) = \frac{C_{3,2}C_{4,0}}{C_{7,2}} = 0.1429

Hence:

p = P(X = 0) + P(X = 2) = 0.2857 + 0.1429 = 0.4286

0.4286 = 42.86% probability of getting 2 of the same colour.

You can learn more about the hypergeometric distribution at brainly.com/question/4818951

3 0
2 years ago
Solve for x please for 10 points
Ira Lisetskai [31]

Answer:

\frac{x-2}{2+1}=\frac{4x-5}{3}

\frac{x-2}{3} =\frac{4x-5}{3}

3*\frac{x-2}{3} =\frac{4x-5}{3}*3

x-2=4x-5

x-2+5=4x-5+5

x-x+3=4x-x

3=3x

\frac{3}{3} =\frac{3x}{3}

1=x

Step-by-step explanation:

your answer is B

7 0
3 years ago
Read 2 more answers
I need help on my homework! 50 points.
Rzqust [24]
Dhdghcdgfgfghdfghfyhfhfhfhfhfh
5 0
3 years ago
Factor 2m^3-12m^2+18m completely
Nina [5.8K]

Answer:

The answer is A.

Step-by-step explanation:

Firstly, you have to take out the common terms for this expression. In this expression, the common terms ard 2 and m :

2 {m}^{3}  - 12 {m}^{2}  + 18m

= 2( {m}^{3}  - 6 {m}^{2}  + 9m)

= 2m( {m}^{2}  - 6m + 9)

Next you have to factorise the brackets :

{m}^{2}  - 6m + 9

=  {m}^{2}  - 3m - 3m + 9

= m(m - 3) - 3(m - 3)

= (m - 3)(m - 3)

=  {(m - 3)}^{2}

So the final answer is :

2m {(m - 2)}^{2}

6 0
3 years ago
Read 2 more answers
Find the value of 21 + 4(32 - 5).<br><br> 37<br> 25<br> 100
bija089 [108]
21+4(32-5)=448


I think it’s 448
4 0
3 years ago
Read 2 more answers
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