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yuradex [85]
3 years ago
10

What is 10 times 5.999999?

Mathematics
2 answers:
Phantasy [73]3 years ago
7 0

Answer:

59.99999

Step-by-step explanation:

thanks hope it helps u........ pls mark me as brainliest.......if it helps☺️

Sergio039 [100]3 years ago
5 0

Answer:

Hello There!!

Step-by-step explanation:

For me it is easier to just move the decimal point,so if it's multiply you move the decimal point to the right nd if it's divide u move it to the left.So the answer is 59.99999.

hope this helps,have a great day!!

~Pinky~

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Free_Kalibri [48]

Hey there!

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3 years ago
An episode of a television show is 60 minutes long when it originally airs with commercials. On a DVD without commercials, the e
ryzh [129]
60-41 1/2=18 1/2 18 1/2 divided by 1/2=37/2*2 (cross cancel 2s)=37
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3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2x%7D" id="TexFormula1" title="\frac{3}{2x}" alt="\frac{3}{2x}" align="absmid
defon

Answer:

x=35/78

Step-by-step explanation:

3/2x-11/5=(7/8)*(64/49)

3/2x-11/5=8/7

3/2x=8/7+11/5

3/2x=117/35

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3 0
3 years ago
Find the arc-length parametrization of the curve that is the intersection of the elliptic cylinder x 2 + y 2/2 = 1 and the plane
storchak [24]

Answer:

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

0 ≤ Ф ≤ 4π.

Step-by-step explanation:

since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))

the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.

We take

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

Note that

  • f(0) = (1,0,-1)
  • f'(\theta) = (\frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2}, cos(\frac{\theta}{\sqrt2})}, \frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2})

Whose square norm is 1/2cos²(Ф/2)+sen²(Ф/2)+1/2cos²(Ф/2) = 1. This is te parametrization that we wanted.

The values from Ф range between 0 an 4π, because the argument of the sin and cos is Ф/2, not Ф, Ф/2 should range between 0 and 2π.

6 0
3 years ago
Hi please help me choose the correct answer I will Mark you brainlst
Yuri [45]

Answer:

it's d

Step-by-step explanation:

8 0
3 years ago
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