Answer:
Option C) describes something that does not have width or depth
Step-by-step explanation:
We are given the following information in the question:
We may define line as:
- A line is a straight one-dimensional figure having no thickness and extending infinitely in both directions.
- A line is sometimes called a straight line.
- It is demonstrated by arrow on both sides showing that it can be extended on both sides.
- A line can be considered undefined term because it tells us about something that does not have width or depth.
- A lines can extend its length in both side infinitely. It contains arrowheads indicating it can extend.
Thus, the correct option is Option C) describes something that does not have width or depth.
Okay I hope this is what you mean. so if you are saying what is between the numbers 3 and 8 we can make an inequality which will cover all the small decimals between the numbers.
There are 2 different equalities that I'm not sure which one you want.
so the first one would be

x is just the variable I chose for this. Now this inequality means that both 3 and 8 are solutions to the problem. x represent all the little numbers in between so to test your answers just plugin the number you're testing in for x. Since 3 is the lowest number it will have a less than or equal to (in this case) sign and 8 is the greatest so that's why the open/greater side is facing the 8. It reads 3 is less than or equal to x and x is less than or equal to 8.
If you meant all number in between 3 and 8 not include either of those numbers than the inequality would be

In this case all the numbers between 3 and 8 are solutions but 3 and 8 will not be solutions. the line under the symbol means it includes the number which come before or after it. The inequality reads 3 is less than x which is less than 8. You can also plugin in an answer to test it in place of x.
If you have any questions or it turns out you meant somthing else please tell me and I'll be happy to help, sorry if this isn't what you meant in the question.
Answer:
sec²(x) - sec(x) + tan²(x) = (sec(x) - 1)(2sec(x) + 1)
Step-by-step explanation:
sec²(x) - sec(x) + tan²(x) =
= sec²(x) - sec(x) + [sec²(x) - 1]
= sec²(x) - sec(x) + [(sec(x) + 1)(sec(x) - 1)]
= sec(x)[sec(x) - 1] + [(sec(x) + 1)(sec(x) - 1)]
= (sec(x) - 1)(sec(x) + sec(x) + 1)
= (sec(x) - 1)(2sec(x) + 1)
Answer: If we define 2:00pm as our 0 in time; then:
at t= 0. the velocity is 30 mi/h.
then at t = 10m (or 1/6 hours) the velocity is 50mi/h
Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:
a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/
Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)
So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/