Answer:
I am pretty sure its
C. Simple random sample
Step-by-step explanation:
Answer:
depends on the equasion!
Step-by-step explanation:
Answer:
A=4, B=3, C=2, D=7 or A=2, B=7, C=4, D=3
Step-by-step explanation:
To factor this, you are looking for factors of 8×21 = 168 that have a sum of 34.
168 = 1×168 = 2×84 = 3×56 = 4×42 = 6×28 = 7×24 = 8×21 = 12×14
The sums of these factor pairs are 169, 86, 59, 46, 34, 31, 29, 26. The factor pair whose sum is 34 is 6×28. This means we can rewrite the expression as ...
8x² +28x +6x +21
Factoring by pairs gives ...
4x(2x +7) +3(2x +7)
(4x +3)(2x +7) ⇒ A=4, B=3, C=2, D=7 or A=2, B=7, C=4, D=3
Answer:
7x-13y=-117
Step-by-step explanation:
I don't know how this question wants me to solve it, but I just used the slope intercept form. So first, start off with y = mx+b. Plug in the slope for m, so 7/13. Then plug in your points for x,y which is 0,9. You'll get 9 = b. So then you have y = 7/13x+9. So now you need to change into standard form. So, multiply by the denominator (13) and you'll get 13y = 7x+117. Then move the variable over and you'll get 13y - 7x = 117. But it doesn't fit any, so then just multiply by -1 and you'll get -13y + 7x = -117.
Answer:
Normal distribution with mean 0.6 and standard deviation 0.035
Step-by-step explanation:
It's a problem related to Population Proportion
In this, p′ = x / n where x represents the number of successes and n represents the sample size. The variable p′ is the sample proportion and serves as the point estimate for the true population proportion. q′ = 1 – p′
<em>The variable p′ has a binomial distribution that can be approximated by the normal distribution</em>
here, X is the number of “successes” where the woman makes the majority of the purchasing decisions for the household. P′ is the percentage of households sampled where the woman makes the majority of the purchasing decisions for the household.
x = 120
n = 200
p’ = 120/200 = 0.6
The sample proportion will follow the normal distribution. The mean of the distribution being p’ = 0.6
The standard deviation for the distribution is calculated as
Standard Deviation = √[(p’) x (1 – p’)/n]
Standard Deviation = √[(0.6) x (0.4)/200] = √0.0012
Standard Deviation = 0.035