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Answer:
Use the Pythagorean theorem for right triangles to solve this
a^2 + b^2 = c^2 where 'a' and 'b' are the legs of the triangle and 'c' is the hypotenuse
so:
8^2 + b^2 = 17^2 solve for the second leg, b
64 + b^2 = 289
b^2 = 289 - 64= 225
b = 15
2π is the period of `y = 1+ tan((1)/(2)x)`