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inysia [295]
3 years ago
8

There is a spinner with 9 equal areas, numbered 1 through 9. If the spinner is spun one time, what is the probability that the r

esult is a multiple of 2 and a multiple of 3?
Mathematics
2 answers:
zimovet [89]3 years ago
7 0

Answer:

2/3 = 0.666 = 66.67%

Step-by-step explanation:

No of multiples of 2 = 4

No. of multiples of 3 =3

6 is common so total unique multiples of 2 and 3 = 4+3-1 = 6

probability = favourable outcomes/total outcomes =6/9=2/3=0.666

tangare [24]3 years ago
5 0

Answer:

If we think of the numbers 1 through nine, only 1 of those numbers is a multiple of 2 AND 3 and that number is 6.

So, basically, the question is asking what is the probability that "6" will appear.  That is a one out of 9 probability or 1/9 or 11.11%

Step-by-step explanation:

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A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
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Which of the following can be modeled with a linear function? Select all that apply.
kobusy [5.1K]

Answer:

Step-by-step explanation: ifk

3 0
3 years ago
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timofeeve [1]

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6 0
3 years ago
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Anika [276]

Answer:

245 flash drives

Step-by-step explanation:

We can assume that the proportion of broken flash drives in the 200 drive sample is the same as the proportion of broken flash drives in the weekly output. Therefore, if we let x be the number of broken flash drives produced that week, we can write the following equation:

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Solving for x, we get:

\frac{7}{200} =\frac{x}{7000}

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Hope this helps!

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