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3 years ago

Suppose PR = 54, solve for QR 4x-1 3x-1 P R

Mathematics

1 answer:

Svet_ta [14]3 years ago

5 0

Answer:

$QR = 23$

Step-by-step explanation:

P, A, and R are collinear.

PR = 54

$PQ = 4x - 1$

$QR = 3x - 1$

To solve for the numerical length of PR, let's generate an equation to find the value of x.

According to the segment addition postulate:

$PQ + QR = PR$

$(4x - 1) + (3x - 1) = 54$ (substitution)

Solve for x

$4x - 1 + 3x - 1 = 54$

Combine like terms

$4x + 3x - 1 - 1 = 54$

$7x - 2 = 54$

Add 2 to both sides

$7x - 2 + 2 = 54 + 2$

$7x = 56$

Divide both sides by 7

$\frac{7x}{7} = \frac{56}{7}$

$x = 8$

$QR = 3x - 1$

Plug in the value of x into the equation

$QR = 3(8) - 1 = 24 - 1$

$QR = 23$

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<h2>Hello!</h2>

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So,

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$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

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Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

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