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Gnom [1K]
3 years ago
12

There are 5 students in a small class. To make a team, the names of 2 of them will be drawn from a hat. How many different teams

of 2 students are possible?
Mathematics
1 answer:
Gwar [14]3 years ago
5 0

Answer:

10 possible teams.

Step-by-step explanation:

5C2

=5!/(5-2)!2!

=5!/3!2!

=5*4*3*2*1/3*2*1*2*1

=5*4/2*1

=20/2

=10

Therefore answer is 10 possible teams....

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ILL GIVE BRAINLIEST. plsss help asap
balu736 [363]

Step-by-step explanation: It should be the second answer.

8 0
3 years ago
A population of size 3,624 grows at a rate of 3% per year, compounded continuously. How big will the population be in 2 years?
rodikova [14]

Answer:

Step-by-step explanation:

The continuous compound formula is

y=Pe^{rt where P is the principle or starting value, r is the growth rate in decimal form, and t is the time in years. For us:

y=3624e^{(.03)(2)}\\y=3624e^{.06}\\y=3624(1.061836547)\\y=3848.09

which would probably round to just 3848 people.

8 0
3 years ago
Simplyfy it -25 + 14 ÷ (5 – 3)​
Gnesinka [82]

Step-by-step explanation:

-25 + 14 ÷ (5-3)

= -25 + 14 ÷ (2)

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6 0
2 years ago
Read 2 more answers
Suppose in the population, the Anger-Out score for men is two points higher than it is for women. The population variances for m
tatuchka [14]

Answer:

a)= 2

b) 6.324

c) P= 0.1217

Step-by-step explanation:

a) The mean of the sampling distribution of X`1- X`2 denoted by ux`-x` = u1-u2 is equal to the difference between population means i.e = 2 ( given in the question)

b) The standard deviation of the sampling distribution of X`1- X`2 ( standard error of X`1- X`2) denoted by σ_X`1- X`2 is given by

σ_X`1- X`2 = √σ²/n1 +σ²/n2

Var ( X`1- X`2) = Var X`1 + Var X`2 =  σ²/n1 +σ²/n2

so

σ_X`1- X`2 =√20 +20 = 6.324

if the populations are normal the sampling distribution X`1- X`2 , regardless of sample sizes , will be normal with mean u1-u2 and variance σ²/n1 +σ²/n2.

Where as Z is normally distributed with mean zero and unit variance.

If we take X`1- X`2= 0 and u1-u2= 2  and standard deviation of the sampling distribution = 6.324 then

Z= 0-2/ 6.342= -0.31625

P(-0.31625<z<0)= 0.1217

The probability would be 0.1217

8 0
3 years ago
What is the recursive rule for the sequence an=5(-2)n-1
Lana71 [14]
Multiplying an odd number of negative factors equals a negative

-5* 2n -1

Calculate the product

the answer is -10n - 1

4 0
3 years ago
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