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4 years ago

Calculate the distance between the points M=(1.-1) and Q = (8. -9) in the coordinate plane.

Mathematics

1 answer:

34kurt4 years ago

8 0

69 hahahahahahahahahahaha

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kakasveta [241]

16=16 zzzzzzzzzzzzzzz

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4 years ago

Read 2 more answers

Which of the following mathematical statements shows "the quotient of a number and six is eight”?

rosijanka [135]

N ÷ 6 = 8
hope this helps good luck! =]

6 0

3 years ago

Approximately 85% of persons age 70 to 84 live in their own household and are income-qualified for home purchases.

miv72 [106K]

Answer:

The probability that exactly two of the four live in their own household and are income-qualified is = .0975

Step-by-step explanation:

Given -

Approximately 85% of persons age 70 to 84 live in their own household and are income-qualified for home purchases.

Probability of sucess ( p ) = 85% =.85

Probability of failure ( q ) = 1 - .85 =.15

n = 4

From combination of n events taking r sucess we use binomial distribution

$P(X = r) = \binom{n}{r}p^{r}q^{n-r}$

where , r = 2

the probability that exactly two of the four live in their own household and are income-qualified is =

$P(X = 2) = \binom{4}{2}0.85^{2}0.15^{4 - 2}$

= $\frac{4!}{(2!)(2!)} \times 0.7225 \times .0225$

= $6 \times 0.7225 \times .0225$

= .0975

4 0

3 years ago

A city has a population of 25,000. The population is expected to increase by 5.5% annually for the next decade.

ra1l [238]

Answer:

The answer will be 0.45%

Step-by-step explanation:

if right plz mark as brainliest

4 0

3 years ago

A computer programmer has an 18% chance of finding a bug in any given program. What is the probability that she does not find a

LiRa [457]

Answer: $(\frac{41}{50})^{10}$

Step-by-step explanation:

Since, According to the question,

The chance of finding a bug in a program = 18%

Thus, the probability of finding the bug in first attempt = $\frac{18}{100}=\frac{9}{50}$

⇒ The probability of not finding any bug in first attempt = $1 - \frac{9}{50} =\frac{41}{50}$

Similarly, in second attempt , third attempt, fourth attempt_ _ _ _ _ tenth attempt, the probability of not finding any bug is also equal to $\frac{41}{50}$

Thus, the probability that she does not find a bug within the first 10 programs she examines

= $\frac{41}{50}\times \frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}$

= $(\frac{41}{50})^{10}$

5 0

3 years ago