Answer:
75 days
Step-by-step explanation:
The multiplier each day is ...
(1/2)^(t/15)
Then we want to find t such that ...
5 = 160·(1/2)^(t/15) . . . . . . 5 mg are left after t days
5/160 = (1/2)^(t/15) . . . . . . divide by 160
1/32 = (1/2)^5 = (1/2)^(t/15) . . . . rewrite the left side
Equating exponents (equivalent to taking logs), we get ...
5 = t/15
5·15 = 75 = t . . . . . multiply by 15 to find t
After 75 days, there will be 5 mg left.
First sequence with common difference:
8-x=y-8
Second sequence:
20-y=y-x
Solving two simultaneous equations:
x=16-y
20-y=y-16+y
y=12
x=4
y=x4−7; y=2
Y=2 (2)=x.4-7
2+4x-7
4x-7=2 get the variable alone by doing the same thing to both sides
4x=9
4x/4=9/4
y=9/4
x=9/4
Answer:
A=Both distributions are nearly symmetric
Step-by-step explanation:
It is a trinomial because it has 3 terms.
