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bazaltina [42]
3 years ago
6

Which expressions are equivalent to the one below. Check all that apply. 16^x

Mathematics
2 answers:
AysviL [449]3 years ago
7 0

Answer:

d and b and f

Step-by-step explanation:


spin [16.1K]3 years ago
4 0

Answer:

the correct answer is: D,A,B (Apex)

Step-by-step explanation:


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Can somebody explain how these would be done? The selected answer is incorrect, and I was told "Nice try...express the product b
trapecia [35]

Answer:

Solution ( Second Attachment ) : - 2.017 + 0.656i

Solution ( First Attachment ) : 16.140 - 5.244i

Step-by-step explanation:

Second Attachment : The quotient of the two expressions would be the following,

6\left[\cos \left(\frac{2\pi }{5}\right)+i\sin \left(\frac{2\pi \:}{5}\right)\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

So if we want to determine this expression in standard complex form, we can first convert it into trigonometric form, then apply trivial identities. Either that, or we can straight away apply the following identities and substitute,

( 1 ) cos(x) = sin(π / 2 - x)

( 2 ) sin(x) = cos(π / 2 - x)

If cos(x) = sin(π / 2 - x), then cos(2π / 5) = sin(π / 2 - 2π / 5) = sin(π / 10). Respectively sin(2π / 5) = cos(π / 2 - 2π / 5) = cos(π / 10). Let's simplify sin(π / 10) and cos(π / 10) with two more identities,

( 1 ) \cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}

( 2 ) \sin \left(\frac{x}{2}\right)=\sqrt{\frac{1-\cos \left(x\right)}{2}}

These two identities makes sin(π / 10) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and cos(π / 10) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}.

Therefore cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}. Substitute,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

Remember that cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting those values,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right]

And now simplify this expression to receive our answer,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right] = -\frac{3\sqrt{5+\sqrt{5}}}{4}+\frac{3\sqrt{3-\sqrt{5}}}{4}i,

-\frac{3\sqrt{5+\sqrt{5}}}{4} = -2.01749\dots and \:\frac{3\sqrt{3-\sqrt{5}}}{4} = 0.65552\dots

= -2.01749+0.65552i

As you can see our solution is option c. - 2.01749 was rounded to - 2.017, and 0.65552 was rounded to 0.656.

________________________________________

First Attachment : We know from the previous problem that cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}, cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting we receive a simplified expression,

6\sqrt{5+\sqrt{5}}-6i\sqrt{3-\sqrt{5}}

We know that 6\sqrt{5+\sqrt{5}} = 16.13996\dots and -\:6\sqrt{3-\sqrt{5}} = -5.24419\dots . Therefore,

Solution : 16.13996 - 5.24419i

Which rounds to about option b.

7 0
3 years ago
HELP!!!! <br><br> -5 3/4 - 3 1/2 = ?
umka21 [38]

Answer:

9.25 or 9 1/4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
If the volume of the pyramid shown is 360 inches cubed, what is its height?
dimaraw [331]

Answer:

9 inches

Step-by-step explanation:

The formula for the volume of a rectangular pyramid is V = \frac{1}{3}(l*w*h)

  • Here we have volume (V), base (L), and width (W)
  • V = 360 in³, L = 12 in, W = 10 in

We need to manipulate the volume equation to solve for the height (H)

  • First we need to multiply both sides by 3 to get rid of the fraction:  3V = L×W×H
  • Then we need to divide both sides by (L×W) to get: \frac{3V}{lw} =h

Now we can plug in the given values:

  • \frac{3(360in^{3}) }{(12 in)(10in)} =\frac{1080in^{3} }{120in^{2} } = 9in
  • The height is 9 inches
4 0
4 years ago
In the triangle abc the side length side are bc=14 and ac=7 whats b
olga2289 [7]

hope this helps you mate

8 0
3 years ago
What will the length of segment I' J' be?<br>​
Ymorist [56]

Answer:

5.333

Step-by-step explanation:

To find the length of dilated I' J' we need to dilate the shape.

To do this you multiply each coordinate by 8/3.

Ex: (x,y) ---> (8/3x, 8/3y)

H: (0,3) ---> (8/3*0, 8/3*3)

I: (1,1) ---> (8/3*1, 8/3*1)

J: (3,1) ---> (8/3*3, 8/3*1)

K: (2,5) ---> (8/3*2, 8/3*5)

Now we plot this. (Picture attached)

The new I' coordinate: (2.667, 2.667)

The new J' coordinate: (8, 2.667)

The new length would be 8 - 2.667 so we can find the distance between the two points.

Note we are subtracting the y coordinates and not x because x coordinates represent height and y represents length

8 - 2.667 equals 5.333

So the length of segment I' J' will be 5.333

5 0
2 years ago
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