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vodka [1.7K]
2 years ago
15

If a machine that prints designs on T-shirts prints 500 shirts in 3 hours, how many hours will it take to print designs on 1,800

shirts?
A.
6

B.
9.8

C.
10.8

D.
12
Mathematics
1 answer:
vivado [14]2 years ago
4 0

Answer:

The answer is D. 12

Step-by-step explanation:

In 3 hours, it prints 500 shirts. That means 6 hours it will print 1,000 shirts, in 9 hours it will print 1,500 shirts, and in 12 hours, it will print 2,000 shirts. So in 12 hours, it will print 1,800 shirts.

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Plzzzz help meeeeeeeee 45 points ASAAAPPPPPPP
lubasha [3.4K]

Answer:

240

Step-by-step explanation:

If you draw a straight line, 12 would meet at 240. Hope this is helpful! You were close but I think you mixed up 240 and 300.

6 0
2 years ago
Read 2 more answers
After 3 minutes, a submarine had descended to −320 feet. After 8 minutes, the submarine had descended to −420 feet. Assuming a l
LiRa [457]

Answer:

d(t) = -20t - 260

Step-by-step explanation:

The depth function is:

d(t) = mt + b

After 3 minutes, a submarine had descended to −320 feet.

This means that d(3) = -320. So

d(t) = mt + b

-320 = 3m + b

After 8 minutes, the submarine had descended to −420 feet.

This means that d(8) = -420. So

d(t) = mt + b

-420 = 8m + b

From the first equation:

b = -320 - 3m

So

-420 = 8m + b

-420 = 8m - 320 - 3m

5m = -100

m = \frac{-100}{5}

m = -20

And

b = -320 - 3*(-20) = -260

So

d(t) = -20t - 260

7 0
3 years ago
a local police station collects winter coats at a rate of 16 coats per week. At this rate, how many coats will they collect in 1
crimeas [40]
16 per 14 equals 224
5 0
3 years ago
Can someone help me plz
UNO [17]
It charged 2.2% per min
4 0
3 years ago
Maria calls her mother 5 times every week. Let w represent the number of weeks and c represent the total number of times Maria c
galina1969 [7]

Answer:

Equation: 5w = c

Step-by-step explanation:

{ \tt{w \:  \alpha \: c}} \\ { \tt{w = kc}}

k is a constant of proprtionality

{ \tt{1 = (k \times 5)}} \\ { \tt{k =  \frac{1}{5} }}

» Therefore, equation becomes:

{ \tt{w =  \frac{1}{5}c }} \\  \\ { \boxed{ \tt{5w = c}}}

8 0
2 years ago
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