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vodka [1.7K]
2 years ago
15

If a machine that prints designs on T-shirts prints 500 shirts in 3 hours, how many hours will it take to print designs on 1,800

shirts?
A.
6

B.
9.8

C.
10.8

D.
12
Mathematics
1 answer:
vivado [14]2 years ago
4 0

Answer:

The answer is D. 12

Step-by-step explanation:

In 3 hours, it prints 500 shirts. That means 6 hours it will print 1,000 shirts, in 9 hours it will print 1,500 shirts, and in 12 hours, it will print 2,000 shirts. So in 12 hours, it will print 1,800 shirts.

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Darlene has 59 pages to type. so far she gas type 23 pages. what fraction of the job is finished ​
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Answer:

\frac{23}{59}

Step-by-step explanation:

A fraction can be found be taking the current amount over the total amount:

\frac{current}{total}=\frac{23}{59}

Since Darlene has only typed 23 pages out of 59, her fraction is 23 over 59.  Fractions must always be in simplest form, which means that both the numerator and denominator can no longer be divided by the same factor.  Since the numbers 23 and 59 are both prime and have no other factors other than 1 and themselves, the fraction 23/59 is in simplest form.

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Between which pair of decimals does the square root of 13 fall between
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Bishon needs to sell at least 0.3 of his collection of sports cards to
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Answer:

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Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

     11 gallons per minute

(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

\implies y=11x-88+153

\implies y=11x+65

When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

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