Answer:
62.07 %
Explanation:
Chemical Formula = (CH3)2CO = C3H6O
Mass of C = 12 g/mol
Mass of H = 1 g/mol
Mass of O = 12 g/mol
Mass of C3H6O = 3(12) + 6(1) + 16 = 58 g/mol
Total mass of C in Acetone = 12 * 3 = 36 g
Mass Percent of C = Total mass of C / Mass of Acetone * 100
Mass percent = 36 / 58 * 100
Mass percent = 62.07 %
