I'm pretty sure its during the anaphase
Answer:
Explained below.
Explanation:
First of all, the orbital path of electron is mostly parabolic in electric field.
In an electric field, electrons behave very similar to a projectile. Thus, Electrons have a parabolic path in an electric field simply because the speed of the electrons in a direction which is perpendicular to the electric field is constant since there is no force. Therefore, there will be no acceleration along that perpendicular direction. However there will be an acceleration that is constant in the direction of the electric field which makes it act in a similar manner to a projectile under gravity.
1) humidity 2) temperature 3) more 4) high 5) low 6) relative 7) divided 8) cloud 9) dew 10) divided. i think this is correct
Types of Bonds can be predicted by calculating the
difference in electronegativity.
If, Electronegativity difference is,
Less
than 0.4 then it is Non Polar Pure Covalent
Between 0.4 and 1.7 then it is Polar Covalent
Greater than 1.7 then it is Ionic
For Br and Br,
E.N of Bromine = 2.96
E.N of Bromine = 2.96
________
E.N Difference
0.00 (Non Polar/Pure Covalent)
For N and O,
E.N of Oxygen = 3.44
E.N of Nitrogen = 3.04
________
E.N Difference
0.40 (Non Polar/Pure Covalent)
For P and H,
E.N of Hydrogen = 2.20
E.N of Phosphorous = 2.19
________
E.N Difference 0.01 (Non Polar/Pure Covalent)
For K and O,
E.N of Oxygen = 3.44
E.N of Potassium = 0.82
________
E.N Difference 2.62 (Ionic)
It would be d.
Reason being said...
the electron configuration normally goes like this...
1s2 2s2 2p6 3s2 3p6 4s2....
until you hit the transition metals..remember those have a special rule..
even though you are in the 4 sublevels for the orbitals ... it goes down 1
Making it 3d..(1,2,3,4,5,6,7,8,9,10)
Going on...
at 5s2 then, 4d1, 4d2, 4d3, 4d4, etc..
at 6s2 then, 5d1, 6d2, 6d3, 6d4, etc..
Thus, D orbital is your answer.
